1. The final amount of each primer required in a PCR reaction is 0.025 nanomol. If the total volume of the PCR reaction is equal to 100 µl and the stock concentration of each primer is equal to 10 µM. Calculate the volume of stock primer that needs to be added in order to ensure a primer amount of 0.025 nanomol. 2. A 250 ml phosphate buffer solution contains 204.12 µg KH2PO4 and 87.09 µg K2HPO4, respectively. Determine the molarities in micromolar (µM) of the abovementioned compounds in the phosphate buffer solution. [Mw KH2PO4 = 136.08 g/mol and Mw K2HPO4 = 174.18 g/mol] 3. You are required to use the pET 28b expression vector in a cloning experiment. If the vector is 5.368 kilobasepairs in length and the mass of the DNA that you have added represent 8.5 x 109 molecules. Determine the mass of vector DNA that you have added to your reaction? [1basepair ~ 660 Da or g/mol, Avogadro’s constant = 6.023 x 1023 molecules/mol]

Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
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1. The final amount of each primer required in a PCR reaction is 0.025 nanomol. If the total volume of the PCR reaction is equal to 100 µl and the stock concentration of each primer is equal to 10 µM. Calculate the volume of stock primer that needs to be added in order to ensure a primer amount of 0.025 nanomol.

2. A 250 ml phosphate buffer solution contains 204.12 µg KH2PO4 and 87.09 µg K2HPO4, respectively. Determine the molarities in micromolar (µM) of the abovementioned compounds in the phosphate buffer solution. [Mw KH2PO4 = 136.08 g/mol and Mw K2HPO4 = 174.18 g/mol]

3. You are required to use the pET 28b expression vector in a cloning experiment. If the vector is 5.368 kilobasepairs in length and the mass of the DNA that you have added represent 8.5 x 10molecules. Determine the mass of vector DNA that you have added to your reaction? [1basepair ~ 660 Da or g/mol, Avogadro’s constant = 6.023 x 1023 molecules/mol]

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