Concept explainers
Use the electro negativity values in Figure 7.4 top redict whether the bonds in the following compounds are non-polar covalent, polar covalent, or ionic. Which is incorrectly labeled?
(a)
(b) CsBr (ionic)
(c)
(d)
(a)
Interpretation:
Whether is non-polar covalent or not needs to be determined.
Concept introduction:
The nature of the compound depends on the difference in the electronegativity of two atoms. The given compound is considered as a non-polar covalent compound if the electronegativity difference between two atoms is less than 0.5. If the electronegtaivity difference is between 0.5 to 1.7 then the bond is polar covalent in nature. If the difference is more than 1.7, the bond between two atoms will be ionic in nature.
Explanation of Solution
The given compound is
According to the given figure in the question, the electronegativity value of Si and Cl is 1.8 and 3.0 respectively.
The difference between the two atoms can be calculated as follows:
Since, the value of
(b)
Interpretation:
Whether
Concept introduction:
The nature of the compound depends on the difference in the electronegativity of two atoms. The given compound is considered as a non-polar covalent compound if the electronegativity difference between two atoms is less than 0.5. If the electronegtaivity difference is between 0.5 to 1.7 then the bond is polar covalent in nature. If the difference is more than 1.7, the bond between two atoms will be ionic in nature.
Explanation of Solution
The given compound is
According to the given figure in the question, the electronegativity value of Cs and Br is 0.7 and 2.8 respectively.
The difference between the two atoms can be calculated as follows:
Since, the value of
(c)
Interpretation:
Whether
Concept introduction:
The nature of the compound depends on the difference in the electronegativity of two atoms. The given compound is considered as a non-polar covalent compound if the electronegativity difference between two atoms is less than 0.5. If the electronegtaivity difference is between 0.5 to 1.7 then the bond is polar covalent in nature. If the difference is more than 1.7, the bond between two atoms will be ionic in nature.
Explanation of Solution
The given compound is
According to the given figure in the question, the electronegativity value of F is 4.0.
The difference between the two atoms can be calculated as follows:
Since, the value of
(d)
Interpretation:
Whether
Concept introduction:
The nature of the compound depends on the difference in the electronegativity of two atoms. The given compound is considered as a non-polar covalent compound if the electronegativity difference between two atoms is less than 0.5. If the electronegtaivity difference is between 0.5 to 1.7 then the bond is polar covalent in nature. If the difference is more than 1.7, the bond between two atoms will be ionic in nature.
Explanation of Solution
The given compound is
According to the given figure in the question, the electronegativity value of C and F is 2.5 and 4.0 respectively.
The difference between the two atoms can be calculated as follows:
Since, the value of
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