You toss a ball from your hand, at height, yi, at an initial speed of 10.00 m/s, at an angle of 30.0∘ above the horizontal. The ball travels for 2.0 seconds before landing on the ground. Ignore air resistance in this problem. 1. Please sketch a picture of the problem 2. List all the known values
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- While standing on the roof of a building, a child tosses a tennis ball with an initial speed of 16 m/s at an angle of 25° below the horizontal. The ball lands on the ground 3.5 s later. How tall, in meters, is the building? m DETAILS OSCOLPHYS2016 3.4.WA.047. MY NOTES ASK YOUR TEACHER A soccer ball, kicked from ground level at an angle of 73.0° above horizontal, is in the air for 4.40 s. What was its initial speed, in m/s, just after it was kicked? Ignore air resistance. m/sA skydiver ejects from his aircraft and falls 80 m from the ground without friction. When he opens his parachute, he decelerates at 3.5 m/s2. The skydiver hits the ground at 5 m/s. How long was the pilot in the air and at what height did he begin his fall? Show the solution and choose the answer. A. 9.8909 s, 459.17 m B. 9.8909 s, 379.17 m C. 13.9295 s, 379.17 m D. 13.9295 s, 459.17 mNeglect air friction unless otherwise specified. Remember that g is the magnitude of the acceleration due to gravity. Use g=10 m/s? for these problems. 1. You throw a snowball from a roof with a speed of 20 m/s at an angle of 36.87° above the horizontal. The ball lands at a horizontal distance of 48 meters from where you throw the snowball. Assume free fall. a. Draw a labeled diagram with all relevant information. Include origin and +x and +y directions. b. How long is the ball in the air? c. How high is the roof? d. What is the speed and direction of the snowball just before it hits the ground? Give angle relative to vertical with zero degrees being straight down.
- A small rocket with a booster blasts off and heads straight upwards. When at a height of 4km and a velocity of 250.0 m/s, it releases its booster. a. What is the maximum height the booster attains?b. What is the velocity of the booster at a height of 6.0 km? Neglect air resistance6. Each of the questions below refers to a projectile that is launched from the top of a tower, 45.0 m above the ground, at a speed of 12.5 m/s at an angle of 40.0° up from horizontal. a. Draw a diagram of the situation, labeling all of the known quantities. Also, use a dashed line to sketch in the path of the projectile from its launch until it hits the ground. b. Find the x and y components of its initial velocity. c. How long does it take to reach its maximum height? d. How high is its maximum height above the ground? e. How long is it in the air before it hits the ground? f. How far away from the base of the tower is it when it hits the ground? g. Find the x and y components of its velocity right before it hits the ground. h. Find its speed right before it hits the ground.You fire a ball with an initial speed V0 at an angle (ϕ) above the surface of an incline, which is itself inclined at an angle (θ) above the horizontal (Figure below). a. Find the distance, measured along the incline, from the launch point to the point when the ball strikes the incline. b. What angle ϕ gives the maximum range, measured along the incline? Ignore air resistance. c. Since there's no air resistance, this is a problem in projectile motion. The goal is to find the point where the ball's parabolic trajectory intersects the incline. It is best to choose the x-axis to be horizontal and direct to the right, the y-axis to be vertical and direct to the up, and the origin to be at the point where the ball is fired. In the projectile equations, the launch angle α0 is measured from the horizontal. What is this angle in terms of (θ) and (ϕ)?
- Jake tested their cannon by launching a cannonball at a bottom of a cliff with initial speed = 40.0 [m/s] directed at an angle = 42.0° above the horizontal, towards a cliff with height h. The cannonball hits the cliff t = 4.50 [s] after the launch. a.)What is the maximum height the cannonball achieved? b.)What is the speed of the cannonball just before impact?Gab, a professional rooftop futbol player, kicked a 0.45 kg ball off a rooftop that is 81 m off the ground, at 15 m/s oriented 45° above his horizon. His pal, Henry, caught the ball from a window at a distant building that is 46 m off the ground. Henry then released the ball from this height and let the ball fall to the ground. A. What is the speed of the ball just before it reaches Henry? B. What is the speed of the ball just before it reaches the ground?A TI Yo Ac As Inv Eva Knc need to: 1. Ignore air resistance when answering all parts of this question. a. A golf ball is hit at 60.0° to the horizontal with an initial velocity of 1.50 x 102 ms¹. It lands at the same height from which it is hit. i. Show that the initial vertical velocity of the ball is 1.30 x 102ms¯ (1) 1/2 ii. Find the time of flight of the golf ball. iii. Calculate the range of the ball. KA1 (1) KA2 (3) KA2 (2) b. A baseball is hit at the same angle and initial speed as the golf ball in part a. However, its initial height is 1.3m above the ground. Explain why the baseball will travel further than the golf ball from part a.
- A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of 20.5 m/s. The cliff is h = 26.0 m above a flat, horizontal beach as shown in the figure. V Ⓡ(Do not type the unit in your answers) A new circus act is called the Texas Tumblers. Lovely Mary Belle swings from a trapeze, projects herself at an angle of 53°, and is supposed to be caught by Joe Bob, whose hands are 6.1 m above and 8.2 m horizontally from her launch point. You can ignore air resistance. a. What initial speed v, must Mary Belle have just to reach Joe Bob? Ans.: m/s b. What is the X-component of her velocity when Mary Belle reaches Joe Bob? Ans.: m/s c. What is the y-component of her velocity when Mary Belle reaches Joe Bob? Ans.: m/sA calculator may not be used on the following questions. A particle moves in the xy-plane so that its velocity vector for time 0 <<10 is (√36-67, 4t). Which one of the following statements is true about the particle when * = 1? Select one: a. The speed of the particle is √30 +4. O b. The particle is at rest. Oc. The particle is speeding up. Od. The particle is slowing down.
