Use the Squeeze Theorem to show that lim x2 co X-0 cos(207TX) = 0. Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(207x), and h(x) = x² on the same screen. Let f(x) = -x², g(x) = x² cos(207x), and h(x) = x². Then 0s cos(207x) s 1 f(x)=x² cos(207x)s ? Since lim f(x)= lim h(x)= x-0 x-0 by the Squeeze Theorem we have lim_ g(x)=
Use the Squeeze Theorem to show that lim x2 co X-0 cos(207TX) = 0. Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(207x), and h(x) = x² on the same screen. Let f(x) = -x², g(x) = x² cos(207x), and h(x) = x². Then 0s cos(207x) s 1 f(x)=x² cos(207x)s ? Since lim f(x)= lim h(x)= x-0 x-0 by the Squeeze Theorem we have lim_ g(x)=
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter4: Calculating The Derivative
Section4.CR: Chapter 4 Review
Problem 5CR: Determine whether each of the following statements is true or false, and explain why. The chain rule...
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![Use the Squeeze Theorem to show that lim x² cos(207TX) = 0.
X → 0
Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(207x), and h(x) = x² on the same screen.
Let f(x) = -x², g(x) = x² cos(207tx), and h(x) = x². Then [0 ✓≤ cos(207TX) ≤ 1
f(x)
V
≤ x² cos(207Tx) ≤ ?
S
. Since lim f(x) = lim_h(x) :
=
X → 0
X → 0
, by the Squeeze Theorem we have lim g(x)
X → 0
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F18574973-f25e-4ab8-b7d6-6007b5b87fc4%2F927defff-7696-45c4-9a35-730a7ec31e24%2Fqilx3oa_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Use the Squeeze Theorem to show that lim x² cos(207TX) = 0.
X → 0
Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(207x), and h(x) = x² on the same screen.
Let f(x) = -x², g(x) = x² cos(207tx), and h(x) = x². Then [0 ✓≤ cos(207TX) ≤ 1
f(x)
V
≤ x² cos(207Tx) ≤ ?
S
. Since lim f(x) = lim_h(x) :
=
X → 0
X → 0
, by the Squeeze Theorem we have lim g(x)
X → 0
=
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