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- For IEEE 754 single-precision floating point, write the hexadecimal representation for positive zero, the smallest positive denormalized number and the largest positive normalized numberJ - For the IEEE 754 single-precision floating point, what is the number, as written in binary scientific notation, whose hexadecimal representation is the following? FF80 0000The value ofa float type variable is represented using the single-precision 32-bit floating point format of IEEE-754 standard that uses I bit for sign, 8 bits for biased exponent and 23 bits for mantissa. A float type variable X is assigned the decimal value of -1425. The representation of X in hexadecimal notation is
- A NEGATIVE NUMBER HAS AN EXPONENT OF 5 AND MANTISSA OF 127.0625 IN 32-BIT FLOATING-POINT REPRESENTATION. IDENTIFY THE NUMBERUsing the signed-1's complement format, the representation of -7 is_ 1000 0111 1111 1001 This is a standard binary code for the alphanumeric characters that uses seven bits to code 128 characters Hollerith Code ASCII Code EBCDIC Code Gray Code This is defined as a single variable within a term, in complemented or uncomplemented form. coefficient of variable unary variable literal constantShow the IEEE 754 binary representation for the following floating- point numbers. a)-6.12510 ➜ To IEEE 754 single precision S E Significand b) +6.12510 To IEEE 754 double precision S E Significand
- X and Y are represented in IEEE single precision floating point notation. Let X = (41D00000)16, Y = (C0000000)16. The result of (x *y) in Decimal isFloating point calculation: a Show the IEEE 754 representation for the decimal value -0.375 in single precision b. Find the decimal representation for the following single precision floating point number 1011,1111,0111,0000,0000,0000,0000,0000 c. Perform the addition and multiplication of the two floating point numbers in (a) and (b) in binary scientific notation, and represent the sum and product in single precision.H - For the IEEE 754 single-precision floating point, write the hexadecimal representation for the following decimal values: (i)–1.0 (ii)– 0.0 (iii)256.015625
- Assume that the numbers A= 88CC3000 and B = 84EA0000 are Typical IBM 32-bit Floating-Point Format numbers: (i) Find A + B (ii) Find A / B (iii) Convert A to the IEEE Single Precision Floating Format (iv) Convert B to the Double Precision IEEE floating point Format.C1640000H is the 32 bit floating point representation (IEEE-754 standard) for the decimal value of x. Then 'x' isThe decimal value -19.625 is equivalent to the IEEE single-precision representation (in hexadecimal starting with 0x... ) Blank 1