The mechanism shown in Figure below has the following link dimensions and construction.. X= 0.3m BD 03. ED= 0.4m Find: EG= 0.4 HF = 0.25 Point F is midpoint of £.G. Link OC is fixed is fixed at O and Rotates Counter- clockwise at 100 r.p.m. C is slider on the link BD, B & G are also fixed points. Slider K also stides in a horizontal path of motion. i) Slider C linear velocity. i) Slider K linear velocity (in) Angular velocity of Link DB.

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The mechanism shown in Figure below has the following
link dimensions and construction.
X = 0.3m
BD-03
ED= 0.4m
Find
EG= 0.4
HF = 0.25
Point F is mid point of EG
Link OC is fixed is fixed at O and Rotates Counter-
clockwise at 100 r.p.m.
C is slider on the link BD,
B & G are also fixed points.
Slider K also slides in a horizontal path of motion.
i) Slider ( linear velocity
ü) Slider K linear velocity
_in) Angular velocity of Link DB.
#
K
G
0
0. 20m 0
e
0,20m
10.05
B
10.10m
TH
G/B
0.05 m
B
Î
0
0.10
M
Transcribed Image Text:The mechanism shown in Figure below has the following link dimensions and construction. X = 0.3m BD-03 ED= 0.4m Find EG= 0.4 HF = 0.25 Point F is mid point of EG Link OC is fixed is fixed at O and Rotates Counter- clockwise at 100 r.p.m. C is slider on the link BD, B & G are also fixed points. Slider K also slides in a horizontal path of motion. i) Slider ( linear velocity ü) Slider K linear velocity _in) Angular velocity of Link DB. # K G 0 0. 20m 0 e 0,20m 10.05 B 10.10m TH G/B 0.05 m B Î 0 0.10 M
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