The formation constant* of [M(CN)2] is 5.30 x 1018, where M is a generic metal.A 0.150 mole quantity of M(NO3) is added to a liter of 0.790 M NaCN solution.What is the concentration of M+ ions at equilibrium?[M²] =M

Given: molM+=0.150mol;[CN−]=0.790M;V=1.00LKf(M(CN)2−)=5.30x10−18;[M+]=???MStep 1: Write the…

Answered: The formation constant* of [M(CN)2] is…

Chemistry & Chemical Reactivity

9th Edition

ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter21: The Chemistry Of The Main Group Elements

Section21.5: The Alkaline Earth Elements, Group 2a

Problem 1Q

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The formation constant* of [M(CN)2] is 5.30 x 1018, where M is a generic metal. A 0.150 mole quantity of M(NO3) is added to a liter of 0.790 M NaCN solution. What is the concentration of M+ ions at equilibrium? [M²] = M