The equilibrium constant for the reaction N₂ + O₂ ⇒ 2NO is 1.69 × 10-³ at 2300 K. A mixture consisting of 2 mol of nitrogen and 1.0 mol of oxygen is heated to 2300 K at 1 bar and allowed to come to equilibrium. Calculate the mole fraction of NO at equilibrium.
The equilibrium constant for the reaction N₂ + O₂ ⇒ 2NO is 1.69 × 10-³ at 2300 K. A mixture consisting of 2 mol of nitrogen and 1.0 mol of oxygen is heated to 2300 K at 1 bar and allowed to come to equilibrium. Calculate the mole fraction of NO at equilibrium.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![The equilibrium constant for the reaction N₂ + O₂2NO is 1.69 × 10-³ at 2300 K. A
mixture consisting of 2 mol of nitrogen and 1.0 mol of oxygen is heated to 2300 K at 1 bar
and allowed to come to equilibrium. Calculate the mole fraction of NO at equilibrium.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d6b1f03-b4bd-4f60-ae23-d8256607755b%2F9b311c5e-0282-4690-ae78-55770e7e8290%2F8zxoa3_processed.png&w=3840&q=75)
Transcribed Image Text:The equilibrium constant for the reaction N₂ + O₂2NO is 1.69 × 10-³ at 2300 K. A
mixture consisting of 2 mol of nitrogen and 1.0 mol of oxygen is heated to 2300 K at 1 bar
and allowed to come to equilibrium. Calculate the mole fraction of NO at equilibrium.
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