Problem 2: Values: FA = 20 N FB = 30 N a = 25° Use the graphical method to determine... a) the magnitude of the resultant force on the bolt. Use the law of cosines for this one. b) the angle made by the resultant, as measured relative to the positive x-axis. Use the law of sines for this one. FA α FB

Problem 2: Values: FA = 20 N FB = 30 N a = 25° Use the graphical method to determine... a) the magnitude of the resultant force on the bolt. Use the law of cosines for this one. b) the angle made by the resultant, as measured relative to the positive x-axis. Use the law of sines for this one. FA α FB

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

a) Resolve F1, F2 and F3 into their rectangular components in xy plane and show them in Cartesian vector notation. b) Find the magnitude of the resultant force(R) in terms of F. c) Determine F provided that the resultant force acting on the ring is required to be minimum. d) Calculate the magnitude and the angle from the x axis (in the CCW direction) of the resultant force using F obtained in the previous part(c).
Graphical Method : Polygon Method F1 - 150N, 30° N of E F2 - 100N, 60° E of S 1) Find the Length and Angle 2) Find Resultant Force Vector Magnitude and %Error 3) Find Resultant Force Vector Direction and %Error
C h kN y bkN a kN In the accompanying sketch, triangle OAB lies in the ry-plane. The component of F represented by line segment AC is parallel to the z-axis. If a = 4.8, b = 7.8, h = 3.9 and B= 27°, express the force F in cartesian vector form. %3D Note that A, B and C do NOT denote points measured with respect to distances; they relate to forces. F = k) kN j+
b) Express the force F as a Cartesian Vector. Assume that the magnitude of F is |Fac] = 771 N. 300 mm A Z B 45° F 60° 60° 100 mm 150 mm
F=z00 30° Calculate the magnitude and direction of the resultant vector. DO NOT USE THE COMPONENT METHOD. Only use the law of sines and cosines to calculate the magnitude of the resultant force. Make sure you show in detail in your paper how you calculated the resultant force. Round your answer to the nearest tenth. Show in detail how you calculated the angle that the resultant force makes with the horizontal counterclockwise. For example
A vector B is 10 cm. long and has a direction – sense of 45°. Vector C is 15 cm. long and has a direction sense of 150°, Find the vector sum or resultant magnitude and its direction by; y 1. Mathematical Solution, 2. Graphical Solution. Scale: 1:1 cm. 3. Draw the position of resultant. 1500 e 450
The position vector rAB = 150i – 85j + TAB2 k has magnitude equal to 188 m. a) Determine the z-component r48 2 (positive). b) If the coordinates of point A are (25, 50, -20)m, define the coordinates of point B. c) Find the angle in degrees of the vector with the y-axis. d) Express a unit vector parallel to rAB in terms of components.
Find the angle between the two given vectors. u = (1, -4, 1), v = (0, 2, –2) %3D Write your answer in degree measure (no need to use the degree symbol), e.g. 45
Determine the magnitude of the vector difference V' = V2 -2V, and the angle 0, which V' makes counterclockwise from the positive x-axis. The angle 0, will be a positive number between 0 and 360°. Complete both graphical and algebraic solutions. You will have to draw an accurate figure for the graphical solution. y V = 28 unit$ V = 31 units 4 2 29° Answers: %3D V' = i units
In the crank-slider shown, OA = 5 cm, AB = 15 cm and the offset e angle a at which slider B reaches the extreme right position. Write your answer in degrees but do not write the unit. 7 cm. Find the value of 7777 x. Answer: DELL
Q1: An aircraft has a hook is subject to four forces as shown in next figure. The direction of the 300 N force may be varied. a) Determine the direction of the 300 N force that make the resultant of the four forces is directed horizontally to the right (posative X-axis). b) Determine the magnitude of the resultant. 100N 150N 260N 300N
Phi = 40 degrees Theta = 35 degrees F1 = 425 Newtons Alpha = 60 degrees Beta = 45 degrees F2 = 625 Newtons a) Find the z-component of F2 in Newtons. If the calculated answer is not whole number, express it in 4 significant figures. If the value is negative, include a negative sign. b) Find the x-component of the Resultant Force in Newtons. If the calculated answer is not whole number, express it in 4 significant figures. If the value is negative, include a negative sign. c) Find the y-component of the Resultant Force in Newtons. If the calculated answer is not whole number, express it in 4 significant figures. If the value is negative, include a negative sign.