Let V be a vector space, and T : V → V a linear transformation such that T(2√1 – 3√₂) = 27₁ + 502 and T(−3v1 + 5√₂) = −4ở1 – 4ʊ2. Then T(v₁) = V₁ + V₂, T(v₂) = v₁+ → T(40₁ − 402) = ₁+ ₂. - V2. V2,
Let V be a vector space, and T : V → V a linear transformation such that T(2√1 – 3√₂) = 27₁ + 502 and T(−3v1 + 5√₂) = −4ở1 – 4ʊ2. Then T(v₁) = V₁ + V₂, T(v₂) = v₁+ → T(40₁ − 402) = ₁+ ₂. - V2. V2,
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.CM: Cumulative Review
Problem 25CM: Find a basis B for R3 such that the matrix for the linear transformation T:R3R3,...
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![Let V be a vector space, and T : V → V a linear transformation such that
T(2√1 – 3√₂) = 27₁ + 502 and T(−3v1 + 5√₂) = −4ở1 – 4ʊ2. Then
T(v₁) =
V₁ +
V₂,
T(v₂) =
v₁+
→
T(40₁ − 402) = ₁+ ₂.
-
V2.
V2,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F553c03f6-c199-4870-a061-8ddf7adde455%2Fe19c5482-de6e-483d-9891-b5ae4d4bf7b5%2Firg63dl_processed.png&w=3840&q=75)
Transcribed Image Text:Let V be a vector space, and T : V → V a linear transformation such that
T(2√1 – 3√₂) = 27₁ + 502 and T(−3v1 + 5√₂) = −4ở1 – 4ʊ2. Then
T(v₁) =
V₁ +
V₂,
T(v₂) =
v₁+
→
T(40₁ − 402) = ₁+ ₂.
-
V2.
V2,
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