Let f(¹) = √2 +2. Since f(x) is differentiable on [-2, 7], by the Mean Value Theorem, we know there exists at least one c in the open interval (-2, 7) such that f'(c) is equal to the mean slope on the interval [ – 2,7]. This function has one such c. Find it using calculus. C = Now give the graphical representation of the Mean Value Theorem in this case: To do this, graph these three things: 1. f(1) = √2+2 2. The secant line through (-2, 0) and (7,3) and 3. The tangent line at the point, c, such that the tangent line is parallel to the secant line.
Let f(¹) = √2 +2. Since f(x) is differentiable on [-2, 7], by the Mean Value Theorem, we know there exists at least one c in the open interval (-2, 7) such that f'(c) is equal to the mean slope on the interval [ – 2,7]. This function has one such c. Find it using calculus. C = Now give the graphical representation of the Mean Value Theorem in this case: To do this, graph these three things: 1. f(1) = √2+2 2. The secant line through (-2, 0) and (7,3) and 3. The tangent line at the point, c, such that the tangent line is parallel to the secant line.
Elementary Algebra
17th Edition
ISBN:9780998625713
Author:Lynn Marecek, MaryAnne Anthony-Smith
Publisher:Lynn Marecek, MaryAnne Anthony-Smith
Chapter6: Polynomials
Section6.6: Divide Polynomials
Problem 6.176TI: Find the quotient: 25x38)(5x2) .
Related questions
Question
![5
4
3
2
1
-6 -5 -4 -3 -2 -1
-1
-2
-3
Clear All Draw:
1 2 3
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Transcribed Image Text:5
4
3
2
1
-6 -5 -4 -3 -2 -1
-1
-2
-3
Clear All Draw:
1 2 3
6 7 8
![Let f(x) = √√√x + 2.
Since f(x) is differentiable on [-2, 7], by the Mean Value Theorem, we know there exists at least one c
in the open interval (-2, 7) such that f'(c) is equal to the mean slope on the interval [ - 2, 7].
This function has one such c. Find it using calculus.
c =
Now give the graphical representation of the Mean Value Theorem in this case:
To do this, graph these three things:
1.
f(x)=√x+2
2. The secant line through (-2, 0) and (7,3)
and
3. The tangent line at the point, c, such that the tangent line is parallel to the secant line.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F54e8c682-be67-4ef0-bd1d-cf8b2e543b76%2Fca991b51-fff8-4061-bee4-b5ffe6c281d4%2Foae8cu_processed.png&w=3840&q=75)
Transcribed Image Text:Let f(x) = √√√x + 2.
Since f(x) is differentiable on [-2, 7], by the Mean Value Theorem, we know there exists at least one c
in the open interval (-2, 7) such that f'(c) is equal to the mean slope on the interval [ - 2, 7].
This function has one such c. Find it using calculus.
c =
Now give the graphical representation of the Mean Value Theorem in this case:
To do this, graph these three things:
1.
f(x)=√x+2
2. The secant line through (-2, 0) and (7,3)
and
3. The tangent line at the point, c, such that the tangent line is parallel to the secant line.
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