◇ KINETICS AND EQUILIBRIUM = Calculating equilibrium composition from an equilibrium constant Suppose a 500. mL flask is filled with 1.7 mol of C12 and 1.8 mol of HC1. The following reaction becomes possible: H2(g) + Cl2(g) 2HCl(g) = The equilibrium constant K for this reaction is 8.45 at the temperature of the flask. Calculate the equilibrium molarity of H₂. Round your answer to two decimal places. Ом ☑ G 0/5
◇ KINETICS AND EQUILIBRIUM = Calculating equilibrium composition from an equilibrium constant Suppose a 500. mL flask is filled with 1.7 mol of C12 and 1.8 mol of HC1. The following reaction becomes possible: H2(g) + Cl2(g) 2HCl(g) = The equilibrium constant K for this reaction is 8.45 at the temperature of the flask. Calculate the equilibrium molarity of H₂. Round your answer to two decimal places. Ом ☑ G 0/5
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 61QRT
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![◇ KINETICS AND EQUILIBRIUM
=
Calculating equilibrium composition from an equilibrium constant
Suppose a 500. mL flask is filled with 1.7 mol of C12 and 1.8 mol of HC1. The following reaction becomes possible:
H2(g) + Cl2(g) 2HCl(g)
=
The equilibrium constant K for this reaction is 8.45 at the temperature of the flask.
Calculate the equilibrium molarity of H₂. Round your answer to two decimal places.
Ом
☑
G
0/5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0402afef-09d2-4ec1-8a39-fe955f91f84a%2F1f3f6b41-2b70-47e0-9d4a-474e7d22467d%2Fk7dd0j_processed.png&w=3840&q=75)
Transcribed Image Text:◇ KINETICS AND EQUILIBRIUM
=
Calculating equilibrium composition from an equilibrium constant
Suppose a 500. mL flask is filled with 1.7 mol of C12 and 1.8 mol of HC1. The following reaction becomes possible:
H2(g) + Cl2(g) 2HCl(g)
=
The equilibrium constant K for this reaction is 8.45 at the temperature of the flask.
Calculate the equilibrium molarity of H₂. Round your answer to two decimal places.
Ом
☑
G
0/5
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