If the diameter of a shaft (X) is normally distributed with mean µ and standard deviation σ, determine the probability density function of the area of cross section of the shaft, fy(y), where y = π x² TT
If the diameter of a shaft (X) is normally distributed with mean µ and standard deviation σ, determine the probability density function of the area of cross section of the shaft, fy(y), where y = π x² TT
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.CR: Chapter 13 Review
Problem 4CR
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![If the diameter of a shaft (X) is normally distributed with mean u and standard deviation o,
determine the probability density function of the area of cross section of the shaft, fy(y), where
= 7x².
Y](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd92a5837-c596-4d2a-9637-c2be3af56cf3%2F65324f55-ad6b-4ec7-9aaf-43fd878f9df0%2Ftmpivxi_processed.png&w=3840&q=75)
Transcribed Image Text:If the diameter of a shaft (X) is normally distributed with mean u and standard deviation o,
determine the probability density function of the area of cross section of the shaft, fy(y), where
= 7x².
Y
![fy(y)
4y
4y
7.9788 [exp{-200( √#7 - 2)²} + exp{-200( − √ − 2)²}]
-
π
TT](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd92a5837-c596-4d2a-9637-c2be3af56cf3%2F65324f55-ad6b-4ec7-9aaf-43fd878f9df0%2Fjpihkb9_processed.png&w=3840&q=75)
Transcribed Image Text:fy(y)
4y
4y
7.9788 [exp{-200( √#7 - 2)²} + exp{-200( − √ − 2)²}]
-
π
TT
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