Explain why structure 4 is a more potent inhibitor (lower IC50 value) than inhibitor 3 and why structure 5 is a much weaker inhibitor (higher IC50 value) than 3 and 4.
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- Given the active site and reaction mechanism, identify the mechanism of irreversible inhibition for the inhibitor provided below. до Active Site HN. Affinity-based inhibitor Mechanism-based inhibitor Transition state analog Non-specific inhibitor Uncompetitive Inhibitor Reaction Mechanism 8+ HN= .00 -EtOH HN Inhibitor OH HN. BrGiven the active site and reaction mechanism below, what is the mechanism of irreversible inhibition of the inhibitor provided? NH+ Active Site Mn²+ *H₂N. HN N NH H₂ Mn²+ +H₂N. HN H₂N "NH₂ Non-specific inhibition Uncompetitive Inhbitor I Transition State Analog Affinity-based inhibition Mechanism-Based Inhibition Reaction Mechanism HN NH *H₂N HN HẠN TÌNH, 2+Mn Mn²+ ‡ +H₂N. H₂N H₂N NH₂ Inhibitor i *H₂N. B но в он OH View site informatData from enzyme inhibition are used to determine a Kmapp and Vmax PP. Comparison of these values with assays run without inhibitor are used to understand how the inhibition is occurring. This is useful for better understanding the active site as well as the practical aspect of pharmaceutical drugs. Below are idealized Line-Weaver Burke plots of different types of inhibitors. Comnetitive Uncomnetitive Mixed +Inh +Inh 4Inh Anh Inh Anh [S] [S] [S] a. How does the value of Vmax for the enzyme compare to the Vmax PP of the inhibited enzyme for: i. Competitive ii. Uncompetitive iii. Mixed b. How does the value of Km for the enzyme compare to the Km PP of the inhibited enzyme for: i. Competitive ii. Uncompetitive iii. Mixed c. For each situation in Model 1, consider an inhibitor that is better than the one shown on the graph. Answer the following questions for each type of inhibition: i. How would the KmPP change? ii. How would the Vmax PP change?
- Given the active site and reaction mechanism below, what is the mechanism of irreversible inhibition of the inhibitor provided? NH* Active Site *H₂N. HN NH₂ +H₂N HN H₂N NH₂* Non-specific inhibition Uncompetitive Inhbitor Transition State Analog i Affinity-based inhibition Mechanism-Based Inhibition Reaction Mechanism *H₂N. NH HN- HN [*] H₂N NH₂ 2+Mn Mn²+ i +H₂N. H₂N i H₂N NH₂ HO Inhibitor *H₂N. B OH r View site informatiWhich of these heterocyclic drugs is likely to be the least soluble in water? Use the Fsp³ parameter to decide. OH Tramadol Chemical Formula: C16H25NO2 YOUR OW Pantoprazole Torasemide Chemical Formula: C16H15F2N3O4S Chemical Formula: C16H20N4O3S Temazepam -OH Chemical Formula: C16H13CIN₂O2 Tioconazole Chemical Formula: C16H13C3N₂OS A. Tramadol B. Pantoprazole C. Torasemide D. Temazepam E. ToconazoleWhy does the apparent KM decrease in the presence ofan uncompetitive inhibitor?
- 1/Vo 1/[S] with I without I with I with I 1/vo without I *-*- 1/vo without I 1/[S] 1/[S] 3. The above graphs are lineweaver-burk plots that demonstrate how inhibitors affect Michaelis Menten enzymes. For each graph identify the type of inhibition and explain how you determined that this enzyme is kinetically demonstrating this type of inhibition.Why does a pure noncompetitive inhibitor not changethe observed KM?The KM values for the reaction of chymotrypsin with two different substrates are given in the table below. Considering this information, which substrate has the lower apparent affinity for the enzyme? Which substrate is likely to give a lower value for Vmax? Substrate N-acetylvaline ethyl ester N-acetyltyrosine ethyl ester KM (M) 8.8 X 10-² 6.6 X 10-4 N-acetylvaline ethyl ester has the lower apparent affinity for the enzyme; it will also likely to give a lower Vmax: N-acetyltyrosine ethyl ester has the lower apparent affinity for the enzyme; it will also likely to give the lower V₁ max. N-acetylvaline ethyl ester has the lower apparent affinity for the enzyme; N- acetyltyrosine ethyl ester is likely to give the lower Vmax: N-acetyltyrosine ethyl ester has the lower apparent affinity for the enzyme; N- acetylvaline will likely to give the lower Vmax. None of the above statements are correct.
- If the new higher KM value is 0.1 mM resulting in the new plot red curve is due to presence of enzyme inhibitor is the inhibitor reversible or irreversible?Match the different names for inhibition mechanisms (1-5) with a description of their properties 7a-7d: 1. competitive inhibitor. 2. allosteric inhibitor also known as non-competitive inhibitor. 3. un-competitive inhibitor. 4. affinity label also known as active site directed covalent (irreversible) enzyme inhibitor. 5. Kcat inhibitor, also known as a mechanism-based covalent (irreversible) enzyme inhibitor. 4a. An enzyme inhibitor in which a substrate or competitive inhibitor is modified so that it contains a chemically reactive electrophile which can bind to and subsequently react with the enzyme active site: 4b. An enzyme inhibitor that contains latent reactive group that upon binding followed by catalytic turnover at the enzyme active site produces a reactive electrophile that reacts covalently with the enzyme: 4c. A reversible inhibitor that competes with the substrate for binding to the enzyme active site: 4d. A reversible inhibitor that can bind independently of substrate to its…draw and label a Michaelis-Menten plot showing the effect of a compentitive inhibitor