Determine the maximum service load P that can be resisted safely by the welded connection shown. Use ASD. E80 10 150 300 K. 200
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- Determine the maximum service load P that can be resisted safely by the welded connection shown. Use ASD. E80 10 150 300 200Design a welded connection for an MC9x23.9 of A572 Grade 50 steel connected to a 3/8-inch-thick gusset plate (Figure 6). The gusset plate is A36 steel. Show your results on a sketch, complete with dimensions. = 3/8" Figure 6 D = 48 k L = 120 k MC9 x 23.9 a. Use LRFD. b. Use ASD.The single 200mm x 10mm steel plate is connected to a 12mm thick steel plate by four 16mm diameter rivets as shown. The rivets used are A502, Grade 2, hot driven rivets. The steel is ASTM A36 with Fu = 400MPa. Determine the value of P in all possible modes of failure and the safe value of P that the connection can resist.
- 1. A riveted lap joint is shown in the figure below. The rivets used are A502, Grade 2, hot-driven with diameter of 16mm. The steel is ASTM A501, 200mm wide and 10mm thick. Determine the safe value of P in all possible modes of failure and the allowable and ultimate value of P that the connection can resist. Use NSCP 2015 200 mam 110 mm P' 10 mmA tension connection consists of A36 steel double angles (two L4x4x1/4 shapes, or 2L4x4x1/4) fastened to a 4x10 No. 2 Red Oak member with a single row of four 0.875 inch A307 bolts. The connection is subjected to normal temperatures but wet in-service conditions. Assume the group action factor is C,=0.95 and the geometry factor is Ca=1. The controlling ASD load combination is D+ L where L is from occupancy. Elevation Cross Section L4x4x1/4 L4x4x1/4 Pa Р. 2L4x4x1/4 4х10 4x10 Plan L4x4x1/4 Pa/2 Pa 4x10 L4x4x1/4 Pa/2 • Determine the load, Pa, that the connection can support based on tension strength of the 4x10. Pa=. lb • Determine the load, Pa, that the connection can support based on gross tension yield of the double angles. The ASD design strength for gross tension yield is F,A,/1.67 where F=36 ksi, A,=1.93 in² for each L4x4x1/4. Pa=. lbConsidering the following steel connection. The plates in Pink are 9mm steel plates. The middle plate (Yellow) is 18mm thick. The width of the plate is 100mm. The maximum allowable tension stresses on any of the plates is 100Mpa in Gross Area Yielding and 150 Mpa for Net Area or Tension Rupture. The bolts used are 8mm in diameter, the holes are 10mm in diameter, no need to add 1.6mm. The bolts allow a maximum of 280 Mpa of shear. Determine the maximum allowable "P" of the connection in kN.
- 5. Find the allowable strength of the welded connection with a minimum throat size shown below. Base metal: S275 Fy = 275N/mm² Fu = 430N/mm² Weld metal tensile strength: Fe = 480N/mm² [all dimensions are in mm] -10mm thick gusset plate 150 125 125 -10mm thick gusset plate 125 VIEW A-A a 125 -PL 150x12 PL 150x12 -PL 150x12 AProblem 7: The load that will be applied to the connection shown has a live load - to - dead load ratio of 3.0. Investigate all limit states. All structural steel is A36, and the weld is a 1/4-inch fillet weld with E70 electrodes. Note that the tension member is a double-angle shape, and both of the angles are welded as shown. Use ASD. Determine the following. 5" 5" 2L5 X 32 X 5/16 LLBB -t = ³/8" Maximum service load that can be applied without exceeding the allowable capacity on yielding on gross area of the tension member (double angle). Maximum service load that can be applied without exceeding the allowable fracture on the net area of the tension member (double angle). Maximum service load that can be applied without exceeding the allowable block shear strength. Considering the weld metal and base metal strength, calculate the maximum service load that can be applied.and corrosion resistance. ity and flexible. D. reusable and cheap. 3. The tension members' strength is not affected by: A. length of connection B. type of fabrication C. length of section D. net area of cross section 4. The failure of pin-connento
- An I-section bracket is connected to the column as shown. The size of weld is 6 mm on web and 10 mm on flange. What will be the safe load (in kN) that can be carried by the connection? Assume NA for whole weld = 110.57 x 106 mm4. Use Fe410 grade steel. 240 mm 170 mm P unu 00t * 280 mm unu 00t 280 mmTwo steel plates are lap jointed in a workshop using 6 mm thick fillet weld as shown in the figure (not drawn to the scale). The ultimate strength of the weld is 410 MPa. 120 mm Fillet weld 200 mm As per Limit State Design is IS 800 : 2007, the design capacity (in kN, round off to three decimal places) of the welded connection, isSTAGGERED CONNECTIONS: A PLATE WITH WIDTH OF 400 mm AND THICKNESS OF 12 mm IS TO BE CONNECTED TO A PLATE OF THE SAME WIDTH AND THICKNESS BY 34 mm DIAMETER BOLTS, AS SHOWN IN THE FIGURE. THE HOLES ARE 2 mm LARGER THAN THE BOLT DIAMETER. THE PLATE IS A36 STEEL WITH YIELD STRENGTH Fy = 248 MPa. ASSUME ALLOWABLE TENSILE STRESS ON NET AREA IS 0.60Fy. IT IS REQUIRED TO DETERMINE THE VALUE OF b SUCH THAT THE NET WIDTH ALONG BOLTS 1-2-3-4 IS EQUAL TO THE NET WIDTH ALONG BOLTS 1-2-4. a. CALCULATE THE VALUE OF b IN MILLIMETERS. b. CALCULATE THE VALUE OF THE NET AREA FOR TENSION IN PLATES IN SQUARE MILLIMETERS. c. CALCULATE THE VALUE OF P SO THAT THE ALLOWABLE TENSILE STRESS ON NET AREA WILL NOT BE EXCEEDED.