correction to this exercice and explain in sentence or two why I made the mis

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Make correction to this exercice and explain in sentence or two why I made the mistake.
hot required
1
1. (3) For the beam shown, in the space provided,
x
a.
500 kN-m
b.
250 N
30°
7.5 m
(2) Draw the Free Body Diagram for the beam
(1) Resolve the distributed load into 2 point loads, and indicate their location as a
0.2.
27m
distance from point O.
missing
reactions
6 kN/m
FRA
6KN/m
FR₂ =
IS KN
FR = EF = FRA + FR₂ + FR3
FR=521 KN/m/
ENGR&214
Fall 2023
0.4 m
4.5 m
30%
15 kN
B
ne tr
A
6 KN M
Öy
FR3
Initials
5m.
0819
0.15 m
+
FR = 521 KN
-442.5 KN
142.5KN/
2. (2) Draw the Free Body Diagram for the bar shown, in the space provided.
uppeR = = (6) (7.5)
FRA
→→16
(ES MRO = -FR₁ (5m) - FR₂ (7.5m) = -6 KN/m (5m) 15KN/m (7.5m)
+
(+5 MR₁ = -)
FR.d = HR d =
500 kN/m
IS KNM
2.5m 1.5m
FR2=(6X45
او الـ الـ
← A
HR
FR
Ау
500 KN/m
a moment!
142.5 KN
500 KNH
d=<0.27 m
Transcribed Image Text:hot required 1 1. (3) For the beam shown, in the space provided, x a. 500 kN-m b. 250 N 30° 7.5 m (2) Draw the Free Body Diagram for the beam (1) Resolve the distributed load into 2 point loads, and indicate their location as a 0.2. 27m distance from point O. missing reactions 6 kN/m FRA 6KN/m FR₂ = IS KN FR = EF = FRA + FR₂ + FR3 FR=521 KN/m/ ENGR&214 Fall 2023 0.4 m 4.5 m 30% 15 kN B ne tr A 6 KN M Öy FR3 Initials 5m. 0819 0.15 m + FR = 521 KN -442.5 KN 142.5KN/ 2. (2) Draw the Free Body Diagram for the bar shown, in the space provided. uppeR = = (6) (7.5) FRA →→16 (ES MRO = -FR₁ (5m) - FR₂ (7.5m) = -6 KN/m (5m) 15KN/m (7.5m) + (+5 MR₁ = -) FR.d = HR d = 500 kN/m IS KNM 2.5m 1.5m FR2=(6X45 او الـ الـ ← A HR FR Ау 500 KN/m a moment! 142.5 KN 500 KNH d=<0.27 m
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