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- Calculate dimensions and power requirements for Flocculator to treat 30000 m3/d wastewater flow. Flocculator should be 4 m deep and maximum 10 m wide.Use following information:μ = 1.003*10-3 Ns/m2 ρ = 999.1 kg/ m3 CD = 1.8 G*t = 3.5*104 Vp = 0.67 m/s 4paddle,4board configurationsCheck the accuracy of the water analysis given in Problem CONSTITUENT Ca+2 Mg¹2 K Na* HCO, CI CO₂ SO₁ -2 CONCENTRATION. g/m² 2.00 85.05 39.10 92.00 61.00 284.00 3.00 288.006- A water plant is designing disinfection process using ozone as a major disinfectant. Based on the test result, the following graph was generated. (ON/NJUI- y = 0.94x R² = 0.99 6 Time (min) where, NO = initial pathogen# per unit volume and N = final pathogen# per unit volume a) Using Chick's law, calculate contact time T (in minute) for 3 log inactivation of pathogen. 2 8 10 b) Plant should meet CT value for 3 log in activation of Giardia Cyst at pH 7.8 and 10° C. What is required ozone concentration in mg/L?
- In a wastewater treatment plant, the supply of oxygen supply is 073 kgO2/h is necessary underoperating conditions, using a mechanical aeration system. Calculate theStandard Oxygen Transfer Rate. Using relevant data: Liquid temperature: T = 23 ◦C, Altitude = 1000 m, DO concentration to be maintained in the liquid CL = 1.5 mg/L, α = 0.90, β = 0.95, θ = 1.024 (Note: calculate the required value if it is missing)ONAN MENDER AYDIN ADNAN MENDERES ÜNİVERSİTESİ IVE ITESI ONLINE SINAV PORTALI 181803026 026 181803026 number for this flow is 181803028 Air flows in a pipe which has 5 cm diameter at a velocity of 4 m/s. dynamic viscosity=1.802x10 and density.1.225 kg/m The Reys 26 181803026 O A) 13596 181803026 181803 O B) 11098 O C) 12605 181803026 O D) 21770 181803026 O E) 16745 Kalan Süre 44 181803026 18180026 181803026 O Bu soruyu cevaplamadan geçmek için bu seçeneği işaretleyin 1818 161803028 Sorunun Cevabı Kaydet ve Sonraki Soruya Geç Antaly 181803026 03028 181802028 1818 181803026 181803026 3818 181803026 181803026 181803026 181803026 181803026 181803026 101803026 18T80300 18180306 18 1818030Determine the preak point dosage of chlorine given the data below which was obtained from chlorination experiment. 5 6 7 Dosage(mg/L) Required Cl₂Cmg/L 0.2 0.45 1.05 2.75 4.5 5.15 6.03 1 2 3 4
- Contaminant X is detected in a drink- ing water supply (4000 m³/day), and 94.99 percent of contaminant X must be re- moved to comply with federal water quality standards. If contaminant X has a "dimen- sionless" Henry's law constant, H, value of 0.25, then what is the design air-to-water flow ratio for an air stripping packed tower, assum- ing 3.5 times the minimum?Q71 Put a circle around the correct ANSWER Evapo-Transpiration is denoted by a) ET b)PT 2/ Evapo-Transpiration means: a) Evaporation + Transpiration 33/Dimensions of Evapo-Transpiration are: a) (m of water/day) b) (m of water/s) c) (m of water/year) Irrigation Cycle le can be calculated by the following formula: a) (dw)A/ET b) (dw)d/ET c) (dw)A/(dw)d 5) Units of Ic are: a) (day/Irrigation) b) (hr/Irrigation) c) (s/Irrigation) ) Porosity of Porous Soil n can be calculated by: a) n= {1-(G/Gs)}x 100 b) n = {1- (Gs/G)} x 100 c) n = {(G/Gs) - 1} 7) Moisture content of porous soil at its saturation condition (wv) s% can be calculated by the following formula: (wv) s%=n% b) (wv) s% = 0.5 n% c) (wv)s% = 2 n% 8) Groundwater flow in Subsurface Tile Drain occurs : a) under effect of pressure b) under effect of gravity 29) Cross-sectional area of Subsurface Tile Drain is: c) TE b) Transpiration c) Evaporation a) less than the cross-sectional area of secondary open drain. b) greater than the…9:10 1 1 4 7 +/- 2 5 8 Question 19 of 20 The hydroxide ion concentration in a solution of NaOH is 2.0 x 10-¹ M at 25 °C. What is the pH of this solution? . 3 60 9 O .5G Tap here or pull up for additional resources Submit XU x 100
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