Choose the CORRECT order of reactions that are conducted by photosystem I. P700 is activated by two photons → two Chl A0 accept two high-energy electrons → one quinone A1 is fully reduced → two electrons are passed on one 4Fe–4S cluster → two molecules of ferredoxin are reduced → ferredoxin–NADP+ reductase takes two protons from the stroma and reduces one NADP+ P680 is activated by two photons → two Chl A0 accept two high-energy electrons → two molecules of ferredoxin are reduced → ferredoxin–NADP+ reductase oxidizes one ferredoxin at a time to reduce FAD to FADH- and then to FADH2 → the proton-motive force is created P700 is activated by a photon → Chl A0 accepts two high-energy electrons → one plastoquinone QA is fully reduced → two electrons are passed on one 4Fe–4S cluster → two molecules of ferredoxin are reduced → ferredoxin–NADP+ reductase takes two protons from the stroma and reduces one FAD P700 is activated by a photon → pheophytin accepts two high-energy electrons → two bound plastiquinones are reduced → cytochrome b6f oxidizes plastoquinols to reduce FAD → two protons are pumped to the stroma P680 is activated by a photon → pheophytin accepts one high-energy electron → one mobile plastiquinone is fully reduced → cytochrome b6f oxidizes plastoquinol to reduce FAD → two protons are pumped to the thylakoid lumen
Choose the CORRECT order of reactions that are conducted by photosystem I. P700 is activated by two photons → two Chl A0 accept two high-energy electrons → one quinone A1 is fully reduced → two electrons are passed on one 4Fe–4S cluster → two molecules of ferredoxin are reduced → ferredoxin–NADP+ reductase takes two protons from the stroma and reduces one NADP+ P680 is activated by two photons → two Chl A0 accept two high-energy electrons → two molecules of ferredoxin are reduced → ferredoxin–NADP+ reductase oxidizes one ferredoxin at a time to reduce FAD to FADH- and then to FADH2 → the proton-motive force is created P700 is activated by a photon → Chl A0 accepts two high-energy electrons → one plastoquinone QA is fully reduced → two electrons are passed on one 4Fe–4S cluster → two molecules of ferredoxin are reduced → ferredoxin–NADP+ reductase takes two protons from the stroma and reduces one FAD P700 is activated by a photon → pheophytin accepts two high-energy electrons → two bound plastiquinones are reduced → cytochrome b6f oxidizes plastoquinols to reduce FAD → two protons are pumped to the stroma P680 is activated by a photon → pheophytin accepts one high-energy electron → one mobile plastiquinone is fully reduced → cytochrome b6f oxidizes plastoquinol to reduce FAD → two protons are pumped to the thylakoid lumen
Chapter20: The Protists
Section: Chapter Questions
Problem 4CT: Melvin Calvin and Andrew Benson determined the steps in the light-independent reactions of...
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Choose the CORRECT order of reactions that are conducted by photosystem I.
P700 is activated by two photons → two Chl A0 accept two high-energy electrons → one quinone A1 is fully reduced → two electrons are passed on one 4Fe–4S cluster → two molecules of ferredoxin are reduced → ferredoxin–NADP+ reductase takes two protons from the stroma and reduces one NADP+
P680 is activated by two photons → two Chl A0 accept two high-energy electrons → two molecules of ferredoxin are reduced → ferredoxin–NADP+ reductase oxidizes one ferredoxin at a time to reduce FAD to FADH- and then to FADH2 → the proton-motive force is created
P700 is activated by a photon → Chl A0 accepts two high-energy electrons → one plastoquinone QA is fully reduced → two electrons are passed on one 4Fe–4S cluster → two molecules of ferredoxin are reduced → ferredoxin–NADP+ reductase takes two protons from the stroma and reduces one FAD
P700 is activated by a photon → pheophytin accepts two high-energy electrons → two bound plastiquinones are reduced → cytochrome b6f oxidizes plastoquinols to reduce FAD → two protons are pumped to the stroma
P680 is activated by a photon → pheophytin accepts one high-energy electron → one mobile plastiquinone is fully reduced → cytochrome b6f oxidizes plastoquinol to reduce FAD → two protons are pumped to the thylakoid lumen
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