1. Consider the following two loops: // Loop A for (i = 1; i <= n; i++) for (j = 1; j<= 10000; j++) sum = sum + j; // Loop B for (i = 1; i <= n; i++) for (j = 1; j
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- PROGRAMMING PROBLEMS For the following programming problems, you need to time a section of code in C++. For example, the following statements time the execution of the function doSomething: #include clock_t start = clock(); doSomething (); clock_t finish = clock(); double overallTime = static_cast (finish - start) / CLOCKS_PER_SEC;3 1. Consider the following two loops: // Loop A for (i = 1; i = n; i++) for (j = 1; j e 10000; j++) sum = sum + j; // Loop B for (i = 1; i <= n; i++) for (j = 1; j <= n; j++) sum = sum + j; What is the Big O ofeach loop? Design and implement an experiment to find a value of n for which Loop B is faster than Loop A. 2. Repeat the previous project, but use the following for Loop B: // Loop B for (i = 1; i <= n; i++) for (j = 1; j <= n; j++) for (k = 1; k <= j; k++) sum = sum + k; 3 CLOCKS_PER_SECOND is a C++ predefined constant.C Programming Problem : Write a C program with a function that takes an integer value (1 <- integer value < 9999) and returns the number with its digits reversed. For example, given the number 6798, the function should return 8976. Those two- original number and reversed number- numbers will pass to another function as parameters and calculate their sum. The program should use the function reverseDigits to reverse the digits and SumOriginalReverse to calculate their sum. Your output should appear in the following format: Output reverse digiS 4321 Main Enter a number between 1 and 9999: 6798 The number with its digits reversed is: 8976 6798 + 8976 - 15774 12.34 JomoriginalRevers Enter a number between I and 9999: 6655 The number with its digits reversed is: 5566 6655 + 5566 = 12221 Enter a number between 1 and 9999: 8 The number with its digits reversed is: 8 8 + 8 = 16 Enter a number between 1 and 9999: 123 The number with its digits reversed is: 321 123 + 321 = 444 Enter a number…In C++ without classes, given a time in 24-hour notation, write a function that adds 2 times, a function that substracts 2 times, and a function that displays the time in 12-hour notation.
- Instructions: In Basic C Language In the code editor, you are provided with a main function that asks the user for an integer input and passes this value to a function called, getFactorial() The getFactorial() function has the following description: Return type - int Name - getFactorial Parameters - one integer Description - returns the factorial of the passed integer Your implementation should be RECURSIVE and you should not use any loops Input #include<stdio.h> int getFactorial(int); int main(void) { int n; printf("Enter n: "); scanf("%d", &n); printf("Factorial of %d is %d", n, getFactorial(n)); return 0;} int getFactorial(int n) { // TODO: Implement this recursive function} Output should be: Enter n: 3 Factorial of 3 is 6C++ Programming: Write a recursive function, sumDigits, that takes an integer as a parameter and returns the sum of the digits of the integer. Also, write a program to test your function. Your program should prompt the user for an integer and output the results to the console.Classwork Requirements: Developa program in C++ that: Reads as many test scores as the user wants from the keyboard (assuming at most 50scores). Test scores should be whole numbers. You must validate user input; only positive numbers are valid. Prints the scores in original order sorted from high to low the highest score the lowest score the average of the scores Implement the following functions using the given function prototypes: void displayArray(int array[], int size)- Displays the content of the array void selectionSort(int array[], int size)- sorts the array using the selection sort algorithm in descending Hint: refer to example 8-5 in the textbook. int findMax(int array[], int size)- finds and returns the highest element of the array int findMin(int array[], int size)- finds and returns the lowest element of the array double findAvg(int array[], int size)- finds and returns the average of the elements of the array
- JAVA CODE PLEASE Recursive Functions Practice ll by CodeChum Admin Create a recursive function named factorial that accepts an integer input as a parameter. This calculates the factorial of that integer through recursion and return it. In the main function, call the factorial function and assign the value to a variable. Print the value in the next line. Input 1. One line containing an integer Output Enter·a·number:·4 24C++ Programming problem: Write a function that takes as a parameter an integer (as a long long value) and returns the number of odd, even, and zero digits. Also write a program to test your function.in C++ Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 2, print "Too small". If greater than 10, print "Too large". Otherwise, compute and print 6 * bagOunces followed by " seconds". End with a newline. Example output for ounces = 7:42 seconds
- C++ Programming problem: Write a program, using a void function, that takes as input an integer and outputs two times the number if it is even; otherwise it outputs five times the number. Then, using a void function, write a program that takes as input two integer values, say n and m. The function returns the sum and average of all the numbers between n and m (inclusive).Computer Science Python question Describe what happens to x when supplying a function with ** within a function call, as in function1(**x).C Program: An integer number is said to be a perfect number if its factors, including 1 (but not the number itself), sum to the number. For example, 6 is a perfect number because 6 = 1 + 2 + 3. I have written a function called isPerfect (see below), that determines whether parameter passed to the function is a perfect number. Use this function in a C program that determines and prints all the perfect numbers between 1 and 1000. Print the factors of each perfect number to confirm that the number is indeed perfect. // isPerfect returns true if value is perfect integer, // i.e., if value is equal to sum of its factors int isPerfect(int value) { int factorSum = 1; // current sum of factors // loop through possible factor values for (int i = 2; i <= value / 2; ++i) { // if i is factor if (value % i == 0) { factorSum += i; // add to sum } } // return true if value is equal to sum of factors if (factorSum == value) { return…