.CI H3C CH3 HN acetone v = 1715 cm1 |(i) higher/lower/same v than acetone (ii) indicate the dominant effect (iii) rank the compounds from highest (1) to lowest (4) in stretching v

EBK A SMALL SCALE APPROACH TO ORGANIC L
4th Edition
ISBN:9781305446021
Author:Lampman
Publisher:Lampman
Chapter95: Nuclear Magnetic Resonance Spectroscopy (proton Nmr)
Section: Chapter Questions
Problem 6P
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Compare the IR carbonyl stretching frequencies of the following compounds to
that of acetone. Compare the table as follows:
(a) State whether the carbonyl stretching frequency is higher, lower, or about the
same
as acetone
(b) State the dominant effect responsible for the change in frequency relative to
acetone (i.e., resonance, inductive, mass change, none)
(c) Rank the compounds with numbers 1 through 4 in order of carbonyl stretching
frequency from highest to lowest (1 = highest; 4 = lowest)
H3C
CH3
HN
acetone
v = 1715 cm-1
|(i) higher/lower/same
v than acetone
(ii) indicate the
dominant effect
(iii) rank the
compounds from
highest (1) to
lowest (4) in
stretching v
Transcribed Image Text:Compare the IR carbonyl stretching frequencies of the following compounds to that of acetone. Compare the table as follows: (a) State whether the carbonyl stretching frequency is higher, lower, or about the same as acetone (b) State the dominant effect responsible for the change in frequency relative to acetone (i.e., resonance, inductive, mass change, none) (c) Rank the compounds with numbers 1 through 4 in order of carbonyl stretching frequency from highest to lowest (1 = highest; 4 = lowest) H3C CH3 HN acetone v = 1715 cm-1 |(i) higher/lower/same v than acetone (ii) indicate the dominant effect (iii) rank the compounds from highest (1) to lowest (4) in stretching v
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