Classical Dynamics of Particles and Systems
5th Edition
ISBN: 9780534408961
Author: Stephen T. Thornton, Jerry B. Marion
Publisher: Cengage Learning
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Chapter 14, Problem 14.3P
Show that the equation
is invariant under a Lorentz transformation but not under a Galilean transformation. (This is the wave equation that describes the propagation of light waves in free space.)
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Chapter 37, Problem 049
A cosmic ray proton passes along the left-right width of a page with a relative speed v and total energy 14.35 nJ. According to your measurements, that
left-right width is 20.0 cm. (a) What is the width according to the proton's reference frame? How much time did the passage take according to (b) your
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Chapter 14 Solutions
Classical Dynamics of Particles and Systems
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- You are in the magic school bus alone. For some reason, you decide to shine a laser straight up. The bus is at a height h = 3.50 m, excluding the wheels, and is travelling at a speed v = 0.800c. Now, your crush is on a car at rest, watching as the bus goes right past.(a) What is the time it takes for the light in your perspective to bounce from the laser to the top of the bus, then to the floor, and back to the laser? (b) Do this same calculation, but for your crush’s perspective. Hint: Light travels at the same speed from any perspective. (c) What is the ratio of the time from your crush’s view and that of your view?arrow_forwardAs you read this page (on paper or monitor screen), a cosmic ray proton passes along the left–right width of the page with relative speed v and a total energy of 14.24 nJ. According to your measurements, that left–right width is 21.0 cm. (a) What is the width according to the proton’s reference frame? How much time did the passage take according to (b) your frame and (c) the proton’s frame?arrow_forwardA linear particle accelerator using beta particles collides electrons with their anti-matter counterparts, positrons. The accelerated electron hits the stationary positron with a velocity of 98 x 106 m/s, causing the two particles to annihilate.If two gamma photons are created as a result, calculate the energy of each of these two photons, giving your answer in MeV (mega electron volts), accurate to 1 decimal place. Take the mass of the electron to be 5.486 x 10-4 u, or 9.109 x 10-31 kg.Note: Assume that the kinetic energy is also converted into the gamma rays, and is included in the two photons.arrow_forward
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