VA= VAX 1 = 100 m/s; of Vax, Two particles of equal mass collide. Before the collision, in the lab frame of reference, particle A is moving along the x-axis with velocity particle B is moving with velocity VB = VBx I + Veyj, with Vax Vey= 10 m/s. (a) Assume, at first, that the collision is totally inelastic. Find the velocity of the two particles together after the collision. (b) Assume, next, that particle B after the collision moves along the x-axis with velocity Vax Vax- Find the values Vay after the collision. Also, find the ratio between initial and final total kinetic energies of the two particles. Is the collision elastic or inelastic? Finally, assume that the collision is elastic and that, if observed in the frame of reference where particle B is at rest, it is a head-on collision. Find the values of VAX. VAY, Vax, Vay in the laboratory frame of reference after the collision.
VA= VAX 1 = 100 m/s; of Vax, Two particles of equal mass collide. Before the collision, in the lab frame of reference, particle A is moving along the x-axis with velocity particle B is moving with velocity VB = VBx I + Veyj, with Vax Vey= 10 m/s. (a) Assume, at first, that the collision is totally inelastic. Find the velocity of the two particles together after the collision. (b) Assume, next, that particle B after the collision moves along the x-axis with velocity Vax Vax- Find the values Vay after the collision. Also, find the ratio between initial and final total kinetic energies of the two particles. Is the collision elastic or inelastic? Finally, assume that the collision is elastic and that, if observed in the frame of reference where particle B is at rest, it is a head-on collision. Find the values of VAX. VAY, Vax, Vay in the laboratory frame of reference after the collision.
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Can you explain part c of this question I attached the solution the part I don’t get is where they say in the solution going back to the frame of reference how are they matching the velocities like that and finding the values
Transcribed Image Text:Problem 2-Collisions in 2D
VA= VAx 1 = 100
m/s;
Assume,
of the two
of VAX,
Two particles of equal mass collide. Before the collision, in the lab frame of reference, particle A is moving along the x-axis with velocity
particle B is moving with velocity VB = VBxi + Veyj, with Vax Vey= 10 m/s. (a)
at first, that the collision is totally inelastic. Find the velocity
particles together after the collision. (b) Assume, next, that particle B after the collision moves along the x-axis with velocity Vax Vax. Find the values
Vay after the collision. Also, find the ratio between initial and final total kinetic energies of the two particles. Is the collision elastic or inelastic? Finally,
assume that the collision is elastic and that, if observed in the frame of reference where particle B is at rest, it is a head-on collision. Find the values of Vax.
VAY, VBx, Vay in the laboratory frame of reference after the collision.
Transcribed Image Text:(b)
We now find
Viết với
Vay = VAy
VAX + VBx =
VAX = VA VB₂
S
=
In this frame of reference, partide B is
at rest, while particle A moves with initial
vebcity, V = VA-Vrel = V₁₂ ↑ + VAY J
Ax
where
5 / 21
- V By
Vet Vaz
V'S
Ax =
77%
(c) Let us consider a frame of reference, S
moving with respect to the laboratory frame
of reference with rekahve vebcity Vret = V3.
-3-
The collision is head-on, and since the two.
particks have equal mass, they exchange
their rebates after the collision: Therefore,
partich A will be at rest in the s-frame
of referen a after the collition:
while partiale B will more at the same
vebaly as particle A. before the collisions
15
Vex = VAN-VBx
1$
Voy
+
Going back to the laboratory frame of
reference, where
VA= V₁ + Vrel : V₂ = ³+ Vrel
we find
VBx
VBY
VBx = VAX
Vax=
Ax
A
Those are indeed the same rebrities that
were found in
part (b) of this problem.
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