Using the curve sketching algorithm developed in class, sketch the graph of f'(x)=5e' (x²+2x-1) f(x)=5e" (x²+4x+1) f(x)=5e³ (x²-1) given Ensure you sketch BY HAND - no technology! Critical points. let f'(x)=0 5e" (x²+2x-1)=0 ↓ DNE x=-1+√2 x=-1-√2 . The critical POI: are at Find FCO) 5e(221) Se° (0²-1) -> ± 1 Points y int at x = -1,1 x=-1+√√2 26--1-√2 let "(x)=0 Se³ (2²+4x+1)=0 -2-√3-2 -2+13=2 2 int let f(x)=0 2 se° (0²-1) =0 5(1)(-1)=0 0=-5 NE ... Pol's at 2=-2-√3 yint at 2=-2+√3 y = -5 Asymptotes: y=0 -> exponitiol + Purchon -1-√√2 -1+-√2 0 local T max at x=-1-√2

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 3E
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ok i need you to create me a full explanation/analysis on this question, I already have the answers for it I just want you to write me an explanation on exactly where the answers came from and stuff. Heres the question and here's the answer I got, so you can add the stuff that I don't have yet. 

What to include:

  • Your function
  • Maximum/minimum points
  • Discontinuities/restrictions
  • Intercepts
  • Domain and Range
  • Intervals of Increase and Decrease
  • Points of Inflection
  • Second derivative test
  • Concavity
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  • Graph
Using the curve sketching algorithm developed in class, sketch the graph of
f'(x)=5e' (x²+2x-1) f(x)=5e" (x²+4x+1)
f(x)=5e³ (x²-1)
given
Ensure you sketch BY HAND - no technology!
Transcribed Image Text:Using the curve sketching algorithm developed in class, sketch the graph of f'(x)=5e' (x²+2x-1) f(x)=5e" (x²+4x+1) f(x)=5e³ (x²-1) given Ensure you sketch BY HAND - no technology!
Critical points.
let f'(x)=0
5e" (x²+2x-1)=0
↓
DNE
x=-1+√2
x=-1-√2
. The critical
POI:
are at
Find FCO)
5e(221)
Se° (0²-1) -> ± 1
Points
y int at
x = -1,1
x=-1+√√2
26--1-√2
let "(x)=0
Se³ (2²+4x+1)=0
-2-√3-2
-2+13=2
2 int
let f(x)=0
2
se° (0²-1) =0
5(1)(-1)=0
0=-5
NE
... Pol's at
2=-2-√3
yint at
2=-2+√3
y = -5
Asymptotes:
y=0 -> exponitiol
+
Purchon
-1-√√2 -1+-√2 0
local
T
max at x=-1-√2
Transcribed Image Text:Critical points. let f'(x)=0 5e" (x²+2x-1)=0 ↓ DNE x=-1+√2 x=-1-√2 . The critical POI: are at Find FCO) 5e(221) Se° (0²-1) -> ± 1 Points y int at x = -1,1 x=-1+√√2 26--1-√2 let "(x)=0 Se³ (2²+4x+1)=0 -2-√3-2 -2+13=2 2 int let f(x)=0 2 se° (0²-1) =0 5(1)(-1)=0 0=-5 NE ... Pol's at 2=-2-√3 yint at 2=-2+√3 y = -5 Asymptotes: y=0 -> exponitiol + Purchon -1-√√2 -1+-√2 0 local T max at x=-1-√2
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