transistor has B=80 The intereledlrede copacitance Cbe=80PF Cbc=2 PF Cce=120PF Ncc be=4R2 LUF R, ike %3D g1o | 244F Effect of R, and Rz negleded. Find the higher cutaoff frequency af the amplifier. A2650kHze705kHz ©265 kHz O 141 KHz 599 kHz

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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transistor has
be=4R2
Ncc
B=80
The interelecirude copacilaue
Cbe=80PF Cbc=2 PF
Cce = 120 PF
Effect of R, and R2 negleded .
LUF R,
Ike:
R2
910244F
l0k2
%3D
Find the higher cut-off frequency af the amplifier.
A2650kHz®705kHz ©265 kHz D 141 KHz e5 99 KHz
B)
Transcribed Image Text:transistor has be=4R2 Ncc B=80 The interelecirude copacilaue Cbe=80PF Cbc=2 PF Cce = 120 PF Effect of R, and R2 negleded . LUF R, Ike: R2 910244F l0k2 %3D Find the higher cut-off frequency af the amplifier. A2650kHz®705kHz ©265 kHz D 141 KHz e5 99 KHz B)
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