The temperature of an exotic liquid in a pipe of length L can be described by the 1D non-dimensional heat equation 8T Ot 8²T a(T) + Q(x, t) 822 with time t, temperature T, temperature dependent thermal diffusivity a(T), and a source term describing additional heating/cooling along the pipe, Q(x, t). On the right end of the pipe, the boundary is adiabatic, 8T On the left end, the fluid has a temperature 8x (x = L, t) = 0. = 2 T(x = 0, t) = 3-sin At t=0 the temperature of the fluid is T(x, t = 0) = 2.5. The thermal diffusivity of the fluid can be modeled by a third-degree polynomial a(T) = ao + a₁T+ a₂T² + a3T³. - 2T (1) (5) For a grid of M + 1 equally spaced points along the pipe and Ar the spacing between points, do the following tasks. Tasks: 6Ar f(x-2) 6f(ri-1) + 3ƒ(x₁) + 2ƒ(x₁+1) 6Ar a) write the equation for the temperature at the last point TM+1 as a function of the neighboring points using a third order accurate finite difference approximation to Eq. (2). Potential third-order finite difference formulas for different stencils using the notation of Table 8.1 are: -2f(x-3) +9f(x₁_2) 18f(r₁_1) | 11ƒ(r.)) +0(Az³¹) +0(Ar³) 2f(x-1)-3f(r₂) | 6ƒ(F;+1) — ƒ(X₁12) +0(Ar) 6AT (2) 11ƒ(x;) + 18ƒ(x4+1) — 9ƒ(*₁+2)+2ƒ(*++3) +.0(Az³) 6A.F (3) (4) (6) (8) (9) b) write the equation for the temperature at the first point 7 using Eq. (3); c) write the equation for the right-hand-side f" of Eq. (1) using Eq. (5) at all non-boundary mesh points à using second-order central finite differences, leaving Q(r, t) as Q(x₁, t") or Q". Use only the above variable names and not any specific parameter values given in later problems.

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Your Question:
The temperature of an exotic liquid in a pipe of length L can be described by the 1D non-dimensional heat equation
8T
Ot
8²T
a(T) + Q(x, t)
822
with time t, temperature T, temperature dependent thermal diffusivity a(T), and a source term describing additional
heating/cooling along the pipe, Q(x, t). On the right end of the pipe, the boundary is adiabatic,
8T
On the left end, the fluid has a temperature
8x
(x = L, t) = 0.
=
2
T(x = 0, t) = 3-sin
At t=0 the temperature of the fluid is
T(x, t = 0) = 2.5.
The thermal diffusivity of the fluid can be modeled by a third-degree polynomial
a(T) = ao + a₁T+ a₂T² + a3T³.
-
2T
(1)
(5)
For a grid of M + 1 equally spaced points along the pipe and Ar the spacing between points, do the following tasks.
Tasks:
6Ar
f(x-2) 6f(ri-1) + 3ƒ(x₁) + 2ƒ(x₁+1)
6Ar
a) write the equation for the temperature at the last point TM+1 as a function of the neighboring points using a
third order accurate finite difference approximation to Eq. (2). Potential third-order finite difference formulas for
different stencils using the notation of Table 8.1 are:
-2f(x-3) +9f(x₁_2) 18f(r₁_1) | 11ƒ(r.))
+0(Az³¹)
+0(Ar³)
2f(x-1)-3f(r₂) | 6ƒ(F;+1) — ƒ(X₁12) +0(Ar)
6AT
(2)
11ƒ(x;) + 18ƒ(x4+1) — 9ƒ(*₁+2)+2ƒ(*++3) +.0(Az³)
6A.F
(3)
(4)
(6)
(8)
(9)
b) write the equation for the temperature at the first point 7 using Eq. (3);
c) write the equation for the right-hand-side f" of Eq. (1) using Eq. (5) at all non-boundary mesh points à using
second-order central finite differences, leaving Q(r, t) as Q(x₁, t") or Q". Use only the above variable names and
not any specific parameter values given in later problems.
Transcribed Image Text:The temperature of an exotic liquid in a pipe of length L can be described by the 1D non-dimensional heat equation 8T Ot 8²T a(T) + Q(x, t) 822 with time t, temperature T, temperature dependent thermal diffusivity a(T), and a source term describing additional heating/cooling along the pipe, Q(x, t). On the right end of the pipe, the boundary is adiabatic, 8T On the left end, the fluid has a temperature 8x (x = L, t) = 0. = 2 T(x = 0, t) = 3-sin At t=0 the temperature of the fluid is T(x, t = 0) = 2.5. The thermal diffusivity of the fluid can be modeled by a third-degree polynomial a(T) = ao + a₁T+ a₂T² + a3T³. - 2T (1) (5) For a grid of M + 1 equally spaced points along the pipe and Ar the spacing between points, do the following tasks. Tasks: 6Ar f(x-2) 6f(ri-1) + 3ƒ(x₁) + 2ƒ(x₁+1) 6Ar a) write the equation for the temperature at the last point TM+1 as a function of the neighboring points using a third order accurate finite difference approximation to Eq. (2). Potential third-order finite difference formulas for different stencils using the notation of Table 8.1 are: -2f(x-3) +9f(x₁_2) 18f(r₁_1) | 11ƒ(r.)) +0(Az³¹) +0(Ar³) 2f(x-1)-3f(r₂) | 6ƒ(F;+1) — ƒ(X₁12) +0(Ar) 6AT (2) 11ƒ(x;) + 18ƒ(x4+1) — 9ƒ(*₁+2)+2ƒ(*++3) +.0(Az³) 6A.F (3) (4) (6) (8) (9) b) write the equation for the temperature at the first point 7 using Eq. (3); c) write the equation for the right-hand-side f" of Eq. (1) using Eq. (5) at all non-boundary mesh points à using second-order central finite differences, leaving Q(r, t) as Q(x₁, t") or Q". Use only the above variable names and not any specific parameter values given in later problems.
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