The polynomial p(x) = (3 – 2x) (x² – 5) is graphed in the coordinate plane. Which statement about the graph is correct? O A. Asx 0o, p (x) -o0 and as → -00, p (a) 0 O B. Asa o, p (x) 0 and as a → -00, p (x) → ∞ O C. As → 0, p (x) → and as x-00, p (x) -0 O D. As x O0, p (x) → -00 and as æ → -0, p(x) → -00

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Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.