Suppose that a ball is dropped from the upper observation deck of the CN Tower in Toronto, 450 m above the ground. Find the velocity of the ball after 3 seconds. Solution The difficulty in finding the velocity after 3 seconds is that we are dealing with a single instant of time (t3), so no time interval is involved. However, we can approximate the desired quaneity by computing the average velocity over the brief time interval of a tenth of a second from t-3 to t3.1. average velocity- Change in position time elapseed a.1)-s(3) 0.1 4.9 0.1 m/s. The following table shows the results of similar calculations of the average velocity over successively smaller time periods. Time Average velocity (m/s) interval 3sts4 34.3 47 3sts3.1 29.89 asts3.05 29.645 asts 3.01 29.449 3sts3.001 29.4049 Thus the (instantaneous) velocity after 3 s is the following m/s (rounded to one decimal place). The instantaneous velocity whent3is defined to be the limiting value of these average velocities over shorter and shorter time periods that It appears that as we shorten the time period, the average velocity is becoming closer to (Round your answer to one decimal place.) m/s

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Suppose that a ball is dropped from the upper observation deck of the CN Tower in Toronto, 450 m above the ground. Find the velocity of the ball after 3 seconds.
Solution
The difficulty in finding the velocity after 3 seconds is that we are dealing with a single instant of time (t = 3), so no time interval is involved. However, we can approximate the desired quantity by computing the average velocity over the brief time interval of a tenth of a second from t= 3 to t= 3.1.
change in position
time elapsed
average velocity =
s(3.1)-s(3)
0.1
4(口
0.1
m/s.
The following table shows the results of similar calculations of the average velocity over successively smaller time periods.
Time
Average
velocity (m/s)
interval
3sts4
34.3
3St5 3.1
29.89
3sts 3.05
29.645
3Sts 3.01
29.449
3 Sts 3.001
29.4049
m/s (rounded to one decimal place). The instantaneous velocity when t=3 is defined to be the limiting value of these average velocities over shorter and shorter time periods that start at t=3. Thus the (instantaneous) velodity after 3sis the following.
It appears that as we shorten the time period, the average velocity is becoming cioser to
(Round your answer to one decimal place.)
%3D
m/s
Transcribed Image Text:Suppose that a ball is dropped from the upper observation deck of the CN Tower in Toronto, 450 m above the ground. Find the velocity of the ball after 3 seconds. Solution The difficulty in finding the velocity after 3 seconds is that we are dealing with a single instant of time (t = 3), so no time interval is involved. However, we can approximate the desired quantity by computing the average velocity over the brief time interval of a tenth of a second from t= 3 to t= 3.1. change in position time elapsed average velocity = s(3.1)-s(3) 0.1 4(口 0.1 m/s. The following table shows the results of similar calculations of the average velocity over successively smaller time periods. Time Average velocity (m/s) interval 3sts4 34.3 3St5 3.1 29.89 3sts 3.05 29.645 3Sts 3.01 29.449 3 Sts 3.001 29.4049 m/s (rounded to one decimal place). The instantaneous velocity when t=3 is defined to be the limiting value of these average velocities over shorter and shorter time periods that start at t=3. Thus the (instantaneous) velodity after 3sis the following. It appears that as we shorten the time period, the average velocity is becoming cioser to (Round your answer to one decimal place.) %3D m/s
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