Professor has made measurements of his household solid waste, shown in the following table. If the container volume is 0.0757 m3, what is the average density of the solid waste produced in his household during the period of time from March 18th through April 8th? Assume that the mass of each empty container is 3.63 kg.
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- From the following date, estimate the unit waste disposal rate per week for a residential area consisting of 1200 homes. The average occupancy is 4 persons per home. The observation location is a local transfer station that receives all of the wastes collected for disposal. The observation period was one week. Data: Number of compactor truck loads = 10 Average size of compactor truck = 20 yd³ Number of flatbed loads = 6 Average flatbed volume = 3 yd³ Number of loads from individual residents' private cars and trucks = 20 Estimated average volume per domestic vehicle = 9 ft³16- The typical composition and characteristics of solid waste sample is ( mass of food waste = 40 kg and density= 250 Kg/m3, mass of Paper and card board = 30 kg and density= 120 Kg/m3, mass of plastic, and rubber = 10 kg and density= 200 Kg/m3 , mass of Garden trimming & wood = 25 kg and density= 150 Kg/m3, mass of Glass, metals, and inerts = 15 kg and density= 300 Kg/m3). The density of remaining solid waste when home - grinder is used and paper and card board component is compacted to 50% of its original volume isAssuming waste not recovered all goes to landfills. Determine the total landfill capacity consumed national wide each year. The specific weights of waste at landfill are as follows. Convert your answer to # of football stadiums filled. Area of football stadium = 1.75 x size of a standard football field Depth of filling = 30 ft Waste category Specific weight (kg/m³) Aluminum 2470 Steel and other metals 7100 Glass 2300 Paper and cardboard 570 Wood 450 All others ~700
- A truck dumped industrial waste into a pit. They found the truck 3 days ago with a pure pool of waste. Your lab finds the BOD5 of this waste to be 80 mg/L with a k=0.1/day. What was the waste source? Here are the 3 nearby suspects: Winery BOD ultimate = 275 mg/L Vinegar manufacturer BOD ultimate = 80 mg/L Pharmaceutical BOD ultimate = 200 mg/LA waste water sample of 2 ml is made upto 300 ml in BOD bottle with distilled water. Initial DO of the sample is 8 mg/l and after 5 days it is 2 mg/1. What is its BOD?The composition of a certain MSW sample and specific weights of its various components are given below: Component Food waste Dirt and ash Plastics Per cent Specific by weight weight (kg/m³) 50 30 10 10 300 500 65 125 Wood and yard waste Specific weight (kg/m³) of the MSW sample is
- Font (1) If the BOD5 of a waste is 220.0 mg/L and the ultimate BOD is 320.0 mg/L, what is the rate constant?Q4 Estimate the energy content of a solid waste sample with the composition below and what is the content on a dry basis and on ash free dry basis? Component Percent by mass Energy kJ/kg Food waste Paper Cardboard Plastics Garden trimming Wood Tin cans Total 15 45 10 10 10 5 5 100 Based on 100 kg sample of waste Moisture content% 70 6 5 2 60 20 3 4,650 16,750 16,300 32,600 6,500 18,600 700Determine the volume of waste
- Equal amounts of two types of waste are disposed into a section of a landfill. They both start producing gas at t=0. Assume first-order decay for gas production. Each type of waste can produce 150 L CH4/kg of waste. Waste type A produces gas with a half-life of 8 years, and waste type B produces gas with a half-life of 4 years. How long (to the nearest year) until 90% of the total gas has been produced? a. 0.8 years b. 6.4 years c. 7 years d. 27.6 years e. 20.4 years Check10. Compute BOD5.20 if BoD1-25 = 95 mg/L for a waste water sample?Following observations were made on a 4% dilution of waste water: DO of aerated water used for dilution = 4 mg/It. DO of diluted sample after 5 days of incubation = 0.8 mg/lt. DO of original waste water sample = 0.5 mg/lt. What is the value of ultimate BOD? [Take Kp (at base 10) = 0.12 day