Let X be the number of widgets that are defective when 3 widgets are randomly chosen and observed. The possible values for X are {0, 1, 2, 3}. The probability mass function for X is as follows. | X | f(x) = P(X = x) | | 0 | 0.550 | | 1 | 0.250 | | 2 | 0.175 | | 3 | 0.025 | Find: - E(X) - Var(X) - F(1) - F(2) - F(3)
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Let X be the number of widgets that are defective when 3 widgets are randomly chosen and observed. The possible values for X are {0, 1, 2, 3}. The
| X | f(x) = P(X = x) |
| 0 | 0.550 |
| 1 | 0.250 |
| 2 | 0.175 |
| 3 | 0.025 |
Find:
- E(X)
- Var(X)
- F(1)
- F(2)
- F(3)
Please include the calculation
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