How many grams of Cl2 can be prepared from the reaction of 16.0g of MnO2 and 30.0g of HCl according to the following balanced chemical equation? MnO2 + 4HCl --> MnCl2 + Cl2 + 2H2O
How many grams of Cl2 can be prepared from the reaction of 16.0g of MnO2 and 30.0g of HCl according to the following balanced chemical equation? MnO2 + 4HCl --> MnCl2 + Cl2 + 2H2O
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter4: Stoichiometry Of Chemical Reactions
Section: Chapter Questions
Problem 75E: How many molecules of the sweetener saccharin can be prepared from 30 C atoms, 25 H atoms, 12 0...
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How many grams of Cl2 can be prepared from the reaction of 16.0g of MnO2 and 30.0g of HCl according to the following balanced chemical equation? MnO2 + 4HCl --> MnCl2 + Cl2 + 2H2O
I figured that MnO2 would be irrelevant because it doesn't have Cl in it. Is this assumption incorrect?
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