For the circuit shown in the following do the following. Find the impedance of the circuit. 150 W * C- 60 p O 15+j 82.17 ohm O 150+j 182.71 ohm O 12+j 12.7 ohm 0 115cos(378t+10) 215+i12.71 ohm 0000 LM 0.6 H
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- "If lab is equal to 595.8252306 and lb is 344296, the phase sequence is:" O POSITIVE O NEGATIVEwhat is the reactive power absorbed by the load ZL in VAR? Assume source is in rmsThe rms value of the resultant current in a wire carries a dc current of 10 A and a sinusoidal alternating current of peak of value 20 A is-
- Shown in the figure below is an "RL" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 9.84 Volts and is running at a frequency of f = 8.585e+04 Hz. The resistor has a resistance of R = 2170 and the inductor has an inductance of L = 3.54e-03 Henries. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Determine the numerical value of Ztot = 2890.5 Determine the numerical value of $z= = 41 Determine the current through the circuit: • I(PEAK) = 4.81E-3 • I(RMS) = 3.404E-3 Determine the voltage across the resistor: • VR(PEAK) = 7.387 • VR(RMS) = 5.22 ✔✔ Amps ✔Amps Write the FORMULA for the phase of the total impedance of the circuit z... = | tan-1 2701 R x Volts X Volts Determine the voltage across the inductor: • VL(PEAK) = 9.184 • VL(RMS) = 6.49 ✔ Volts Volts L R²+ WL- ✔ degrees 2 If a second circuit were connected in parallel with the inductor, this circuit would be considered as: O a low-pass filter O a capacitive switcher…For the following parts, identify the name of each circuit, plot the output waveform, and find the DC output average voltage. Part (a) V 1 cycle V₁ = V sin cor Part (b) PE Part (c) Vm Vi ele eeeeeeeeeeeeee D D₂ D₁ D₂ R Va + D₂ D₁can you please give me the comple solution for this question, thanks. A certain voltage function contains a constant term, a fundamental and third harmonic. The maximum value of the fundamental is 85 % of the constant term and the maximum value of the third harmonic is 55 % of the constant term. If the effective value of this function is 180.3V, find the magnitude of the two harmonics. A.IstHarmonic = 75 V , 3rd Harmonic = 120V B. Ist Harmonic = 80 V , 3rd Harmonic = 125V C. IstHarmonic = 120 , 3rd Harmonic = 75V D. Ist Harmonic = 125 V , 3rd Harmonic = 80V E. NOTA
- Shown in the figure below is an "RC" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 11.58 Volts and is running at a frequency of f = 1.326e+04 Hz. resistor has a resistance of R = 3750 2 and the capacitor has an capacitance of C = 3.17e-09 Farads. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Write the FORMULA for the phase of the total impedance of the circuit tot = Determine the numerical value of Ztot = Determine the numerical value of Pztot= Determine the current through the circuit: • I(PEAK) = • I(RMS) = Determine the voltage across the resistor: Amps Amps S2 C degreesThe peak to peak distance of a sinusoidal waveform displayed on a C.R.O. screen is 9 cm and the 'volts/cm' switch is on 25 V/cm. The peak voltage is given by O 2.78 V O 159.07 V O 112.50 V O 225.00 VIn an experiment, the function generator is adjusted to generate a square voltage at a certain frequency. This voltage is displayed on an oscilloscope and the reading is 10 V peak-to-peak. The rms value of this voltage is .What will be the rms value of this voltage if the frequency is reduced to the half value? 3.536 Vrms . 3.536 Vrms O 5 Vrms . 1.7677 Vrms O 3.536 Vrms. 1.7677 Vrms O 5 Vrms . 5 Vrms ...... O 10 Vrms . 10 Vrms ......
- For the circuit shown below, determine the voltage of the -j10 capacitive reactance. -jsa jl0n 0.5L-90 ILOA(1 -j102 jsn 52 102 AThe peak distance of a sinusoidal waveform displayed on a C.R.O. screen is 6 cm and the 'volts/cm' switch is on 33 V/cm. The peak to peak voltage is given by O 396.00 V O 5.50 V O 139.99 V O 99.00 VThe average value of sinusoidal varying voltage is more than its r.m.s. value. Select one: O True O False Which of the following formula is CORRECT? a. E= - L d0/dt O b. E = - N dl/dt O . L= NI / O O d. W = 0.5 12L In a step down transformer, number of turns in the primary winding is lesser than the number of turns in the secondary winding. Select one: O True O False