(d) Prove that for a classical particle moving from left to right in a box with constant speed v, the average position < x >= (1/T) x(t) dt = L/2, where T = L/v is the time taken to move from left to right. And < x² >= = (1/T) S™ x² (t) dt : L2/3. Hint: Only consider a particle moving from left x = 0 to right x L = and do not include the bouncing motion from right to left. The results for left to right are independent of the sense of motion and therefore the same results apply to all the bounces, so that we can prove it for just one sense of motion. Thus, the classical result is obtained from the Quantum solution when n >> 1. That is, for large energies compared to the minimum energy of the wave-particle system. This is usually referred to as the Classical Limit for Large Quantum Numbers.

icon
Related questions
Question

use T.= L/v, and also what should be the expression of x(t)? is it v*T? 

(d) Prove that for a classical particle moving from left to right in a box with constant
speed v, the average position < x >= (1/T) ff x(t) dt = L/2, where T L/v
is the time taken to move from left to right. And < x² >= : (1/T) ² x² (t) dt
L²/3. Hint: Only consider a particle moving from left x = 0 to right x = L
=
and do not include the bouncing motion from right to left. The results for left
to right are independent of the sense of motion and therefore the same results
apply to all the bounces, so that we can prove it for just one sense of motion.
Thus, the classical result is obtained from the Quantum solution when n >> 1.
That is, for large energies compared to the minimum energy of the wave-particle
system. This is usually referred to as the Classical Limit for Large Quantum
Numbers.
Transcribed Image Text:(d) Prove that for a classical particle moving from left to right in a box with constant speed v, the average position < x >= (1/T) ff x(t) dt = L/2, where T L/v is the time taken to move from left to right. And < x² >= : (1/T) ² x² (t) dt L²/3. Hint: Only consider a particle moving from left x = 0 to right x = L = and do not include the bouncing motion from right to left. The results for left to right are independent of the sense of motion and therefore the same results apply to all the bounces, so that we can prove it for just one sense of motion. Thus, the classical result is obtained from the Quantum solution when n >> 1. That is, for large energies compared to the minimum energy of the wave-particle system. This is usually referred to as the Classical Limit for Large Quantum Numbers.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 7 images

Blurred answer