& = 24.0 V 0.10 n R, 5.0 2 R S20 2 E2- 48.0 V R 0.50 2 40 2 R 78 2 Ez- 6.0 V E 36.0 V Write the equation which results from applying the loop rule to loop akledcba. If the current going through the center of the loop is 45 A, what is the current going through the top, in amps?

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& = 24.0 V
b
0.10 2
R,
5.0 Ω.
E- 48.0 V
R
20 Ω
R
a
0.50 2
40 Q
20.20 2
R
78 Ω
E3 6.0 V
Er 36.0 V
i 0.05 Q h
Write the equation which results from applying the loop rule to loop akledcba.
0 =
If the current going through the center of the loop is 45 A, what is the current going through the top, in amps?
I =
Transcribed Image Text:& = 24.0 V b 0.10 2 R, 5.0 Ω. E- 48.0 V R 20 Ω R a 0.50 2 40 Q 20.20 2 R 78 Ω E3 6.0 V Er 36.0 V i 0.05 Q h Write the equation which results from applying the loop rule to loop akledcba. 0 = If the current going through the center of the loop is 45 A, what is the current going through the top, in amps? I =
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