An experiment was conducted to compare grass seedling growth by treating the seedling soil with one of two fertilizers. Twenty-five of 100 seedlings were randomly chosen to receive Fertilizer X. The rest received Fertilizer Y. The heights were recorded for each seedling, in centimeters, at the end of the study. The results obtained are shown. Fertilizer X: X₁ = 56.2 cm, s₁ = 8 centimeters Fertilizer Y X2 = 64.5 cm, s₂ = 7 cm We wish to determine whether there is a difference in height for the seedlings treated with the different fertilizers by testing the hypotheses Ho: H2 - μ₁ = 0 and Ha: µ2 - μ10. Find the 90% confidence interval for μ2- μ₁ and make a conclusion based on that confidence interval. O The 90% confidence interval is 8.3 ± 3.024. I would not reject the null hypothesis of no difference at the 0.10 level. ○ The 90% confidence interval is 8.3 ± 5.28. I would not reject the null hypothesis of no difference at the 0.10 level. ○ The 90% confidence interval is 8.3 ± 5.28. I would reject the null hypothesis of no difference at the 0.10 level. O The 90% confidence interval is 8.3 ± 3.024. I would reject the null hypothesis of no difference at the 0.10 level. O The 90% confidence interval is 8.3 ± 11.32. The p-value is less than 0.10.
An experiment was conducted to compare grass seedling growth by treating the seedling soil with one of two fertilizers. Twenty-five of 100 seedlings were randomly chosen to receive Fertilizer X. The rest received Fertilizer Y. The heights were recorded for each seedling, in centimeters, at the end of the study. The results obtained are shown. Fertilizer X: X₁ = 56.2 cm, s₁ = 8 centimeters Fertilizer Y X2 = 64.5 cm, s₂ = 7 cm We wish to determine whether there is a difference in height for the seedlings treated with the different fertilizers by testing the hypotheses Ho: H2 - μ₁ = 0 and Ha: µ2 - μ10. Find the 90% confidence interval for μ2- μ₁ and make a conclusion based on that confidence interval. O The 90% confidence interval is 8.3 ± 3.024. I would not reject the null hypothesis of no difference at the 0.10 level. ○ The 90% confidence interval is 8.3 ± 5.28. I would not reject the null hypothesis of no difference at the 0.10 level. ○ The 90% confidence interval is 8.3 ± 5.28. I would reject the null hypothesis of no difference at the 0.10 level. O The 90% confidence interval is 8.3 ± 3.024. I would reject the null hypothesis of no difference at the 0.10 level. O The 90% confidence interval is 8.3 ± 11.32. The p-value is less than 0.10.
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.8: Analyzing Functions With Successive Differences
Problem 39PFA
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Transcribed Image Text:An experiment was conducted to compare grass seedling growth by treating the seedling soil with one of two fertilizers. Twenty-five of 100 seedlings were randomly chosen to receive Fertilizer X. The rest received
Fertilizer Y. The heights were recorded for each seedling, in centimeters, at the end of the study. The results obtained are shown.
Fertilizer X: X₁ = 56.2 cm, s₁ = 8 centimeters
Fertilizer Y X2 = 64.5 cm, s₂ = 7 cm
We wish to determine whether there is a difference in height for the seedlings treated with the different fertilizers by testing the hypotheses Ho: H2 - μ₁ = 0 and Ha: µ2 - μ10. Find the 90% confidence interval for μ2-
μ₁ and make a conclusion based on that confidence interval.
O The 90% confidence interval is 8.3 ± 3.024. I would not reject the null hypothesis of no difference at the 0.10 level.
○ The 90% confidence interval is 8.3 ± 5.28. I would not reject the null hypothesis of no difference at the 0.10 level.
○ The 90% confidence interval is 8.3 ± 5.28. I would reject the null hypothesis of no difference at the 0.10 level.
O The 90% confidence interval is 8.3 ± 3.024. I would reject the null hypothesis of no difference at the 0.10 level.
O The 90% confidence interval is 8.3 ± 11.32. The p-value is less than 0.10.
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