71/2 0.032 kg mol1 (0.032 kg mol¯)(300 m s-1)2 ] exp -1 [27(8.3145 J K-1 mol)(300 K) 2(8.3145 J K-l mol)(300 K) ] =1 = 8.022 X 10 4 s m

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter6: Solutions And Colloids
Section: Chapter Questions
Problem 6.29P
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Explain the calculation process in detail.
-1
1/2
0.032 kg mol
exp
2 7(8.3145 J K-1 mol¯')(300 K)]
(0.032 kg mol)(300 m s-1)2
2(8.3145 J K-l mol)(300 K),
-4
-1
= 8.022 X 10
s m
Transcribed Image Text:Explain the calculation process in detail. -1 1/2 0.032 kg mol exp 2 7(8.3145 J K-1 mol¯')(300 K)] (0.032 kg mol)(300 m s-1)2 2(8.3145 J K-l mol)(300 K), -4 -1 = 8.022 X 10 s m
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