5. A DNA sequence of "ACG" will code for the amino acid First mRNA base (5' end of codon) U G UUU UUC UUA UUG CUU CUC CUA CUG U GUU GUC GUA GUG Phe Leu Leu AUU AUC lle AUA AUG Mato start Val Second mRNA base C A UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Ser Pro The Ala UAU UGU Cys UAC UGC UAA Stop UGA Stop UAG Stop UGG Trp CAU CAC CAA CAG AAU AAC AAA AAG GAU GAC GAA GAG Tyr His Gin Asn Lys Asp Glu G CGU CGC CGA CGG AGU AGC AGA AGG GGU GGC GGA GGG Arg Ser Arg Gly DURG SCAG! U с A G U C G Third mRNA base (3' end of codon) Ang (R) Ala Ser (S) Lys (K) Gl Asp (E) (D) Asn (N) U G 1765100 Gly (G) Thr (1) Met (M) _______. (LS1-1) * AGU GU Lou (F) ( CHOUCHOSCY C OFCUOPCUGACUGACUCA CUOT le (1 AC CUGA GU G U Ser (S) Arg (R) Gh (Q) Hs (H) Tyr (3) Cys (C) Trp (W) Leu () Pro (P)
5. A DNA sequence of "ACG" will code for the amino acid First mRNA base (5' end of codon) U G UUU UUC UUA UUG CUU CUC CUA CUG U GUU GUC GUA GUG Phe Leu Leu AUU AUC lle AUA AUG Mato start Val Second mRNA base C A UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Ser Pro The Ala UAU UGU Cys UAC UGC UAA Stop UGA Stop UAG Stop UGG Trp CAU CAC CAA CAG AAU AAC AAA AAG GAU GAC GAA GAG Tyr His Gin Asn Lys Asp Glu G CGU CGC CGA CGG AGU AGC AGA AGG GGU GGC GGA GGG Arg Ser Arg Gly DURG SCAG! U с A G U C G Third mRNA base (3' end of codon) Ang (R) Ala Ser (S) Lys (K) Gl Asp (E) (D) Asn (N) U G 1765100 Gly (G) Thr (1) Met (M) _______. (LS1-1) * AGU GU Lou (F) ( CHOUCHOSCY C OFCUOPCUGACUGACUCA CUOT le (1 AC CUGA GU G U Ser (S) Arg (R) Gh (Q) Hs (H) Tyr (3) Cys (C) Trp (W) Leu () Pro (P)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
Related questions
Question
![Final Assessment for Exploring M X
forms/d/e/1FAIpQLSe8RrfvHEr59pISGjbEneL041GxKTvyw9-Xc_EA7Um_8xqReA/viewform?hr_submission-Chg1990yzQ8SEAjwvY285...
First mRNA base (5) end of codon)
A
Sequence C
Sequence D
5. A DNA sequence of "ACG" will code for the amino acid
UUG
CUC
CUA
CUG
wh
GUC
GJA
GUG
Cys
100
AUU
AUC lle ACC
AUA
ACA
AUG MACG]
Val
M
Second mRNA base
UCA
UCG
The
GCU
GCC..
GCA
GIGA
CAA
CAG
Tyr
UAC
UGC
UAA Stop UGA Stop A
UAG Stop UGG Tro
AAU
AAC
MT
AAC
GAC
GAG
2
Lys
Asp
CGA
CGG
AGU
AGC
AGA
AGG
Lys
GGU
GGC
GGA
GGG
Arg
DUAU
Gly
C
Third mRNA base (3' end of codon)
Lys (K)
DELL
C
GU
A
C
DEOTOCCAGUCAGUCAGUCHOSOTOS
M
G
(F)
A
(LS1-1) *
GU
A C
CUGA
OPCUGACU GACUSACCO
AD
A
G
OCO
Trp (W)
\u«
9799%3Fo
33
4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5f7ae1f6-4bab-4d6a-9dc2-ad5b53a532ce%2F8631011e-6b11-4d4e-9a97-aa651f9b3e58%2Fjxprdt8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Final Assessment for Exploring M X
forms/d/e/1FAIpQLSe8RrfvHEr59pISGjbEneL041GxKTvyw9-Xc_EA7Um_8xqReA/viewform?hr_submission-Chg1990yzQ8SEAjwvY285...
First mRNA base (5) end of codon)
A
Sequence C
Sequence D
5. A DNA sequence of "ACG" will code for the amino acid
UUG
CUC
CUA
CUG
wh
GUC
GJA
GUG
Cys
100
AUU
AUC lle ACC
AUA
ACA
AUG MACG]
Val
M
Second mRNA base
UCA
UCG
The
GCU
GCC..
GCA
GIGA
CAA
CAG
Tyr
UAC
UGC
UAA Stop UGA Stop A
UAG Stop UGG Tro
AAU
AAC
MT
AAC
GAC
GAG
2
Lys
Asp
CGA
CGG
AGU
AGC
AGA
AGG
Lys
GGU
GGC
GGA
GGG
Arg
DUAU
Gly
C
Third mRNA base (3' end of codon)
Lys (K)
DELL
C
GU
A
C
DEOTOCCAGUCAGUCAGUCHOSOTOS
M
G
(F)
A
(LS1-1) *
GU
A C
CUGA
OPCUGACU GACUSACCO
AD
A
G
OCO
Trp (W)
\u«
9799%3Fo
33
4
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