4₁ P Answer: 90° L2 Ľ. X For the beam shown, you are provided the values P = 590 N downwards, L1= 2 m and L2 = 10 m. Calculate the vertical reaction at the right hand end of the beam. Note the sign convention. Vertical forces are positive if they are pointing in the positve y direction (up) and negative if it is pointing down. When entering a positive number just give the number without the plus sign. Include the minus sign for negative numbers. Give your answer rounded to the nearest whole newton. Include the correct units.

4₁ P Answer: 90° L2 Ľ. X For the beam shown, you are provided the values P = 590 N downwards, L1= 2 m and L2 = 10 m. Calculate the vertical reaction at the right hand end of the beam. Note the sign convention. Vertical forces are positive if they are pointing in the positve y direction (up) and negative if it is pointing down. When entering a positive number just give the number without the plus sign. Include the minus sign for negative numbers. Give your answer rounded to the nearest whole newton. Include the correct units.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=3.5 m, b=5.0 m, MB = 110 kN-m and MC = 145 kN-m. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.)Determine the bending moment acting at each of the following locations:(a) x = 3.5– m (i.e., just to the left of B)(b) x = 3.5+ m (i.e., just to the right of B)(c) x = 8.5– m (i.e., just to the left of C)(d) x = 8.5+ m (i.e., just to the right of C)When entering your answers, use the bending moment sign convention.Answers:(a) M =  kN-m.(b) M =  kN-m.(c) M =  kN-m.(d) M =  kN-m.
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=3.5 m, b=5.0 m, MB = 110 kN-m and MC = 145 kN-m. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.)Determine the shear force acting at each of the following locations:(a) x = 0+ m (i.e., just to the right of point A)(b) x = 3.5– m (i.e., just to the left of B)(c) x = 3.5+ m (i.e., just to the right of B)(d) x = 12.0– m (i.e., just to the left of D)When entering your answers, use the shear force sign convention.Answers:(a) V =  kN.(b) V =  kN.(c) V =  kN.(d) V =  kN.
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=3.5 m, b=5.0 m, MB = 110 kN-m and MC = 145 kN-m. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.)Answers: Ay =    kN, Dy =    kN.
force, the sign convention is same as that used in lectures and seminars). A simply supported beam is loaded as shown in the Figure. The corresponding SFD and BMD would be: 20 kN 10 kN/m 2 m 2 m 30 kN (a) 40 kN m 30 kN 30 kN 10 kN (b) 40 kN.m 10 kN 30 kN 30 kN Click Save and Submit to save and submit. Click Save All Answers to save all answvers.
Help Save & Exit Check Required information A rope connecting points A and B supports the force Fshown in the figure. Write expressions using Cartesian vector representation for the following. Take L= 8 ft and F= 12 lb. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. B 30° F T AB : the position vector from A to B. TAB of 17 Next > < Prev 6. 9. 41
Q1: For the beam Shown in Figure 1 16kN 4kN/m 4kN/m .A C B 3m 2m 2m 3m Figure 1 I. Find the reaction at support A RAy II. Find the reaction at support B RBy III. Find the bending moment at A IV. Find the bending moment at C V. Find the maximum absolute value of the shear force in the beam VI. Draw the shear force and bending moment diagram for the beam
The beam is supported by a fixed support at point A. There are 2 distributed loads applied to the beam. Neglect the weight and thickness of the beam. Take the origin for all functions to be at A. , i.e. start at the left and go right. Must use positive sign convention for V and M. W1 A W2 d1 Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value di 3 m W1 6 (kN)/m W2 3 (kN)/m a. For the interval 0 < x < 3 m, determine the equation for the Shear Force as a function of x, V(x). b. For the interval 0 < x < 3 m, Use integrals to determine the equation for the Moment as a function of X, M(x). o Enter the coefficient of the x term as a fraction and the rest as decimals. for example, x4 1.4x c. Determine the magnitude of the max shear on the beam,Vmax d. Determine the magnitude of the max bending moment on the beam, Mn max
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=3.5 m, b=5.0 m, Mg = 60 kN-m and Mc = 85 kN-m. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. MB Mc D. Calculate the reaction forces A, and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since A = 0, it has been omitted from the free-body diagram.) Mg D D, Answers: Ay = i kN, Dy = kN.
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=4.0 m, b=2.5 m, PB = 4 kN, PC = 4 kN, and MB = 60 kN-m. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.Calculate the reaction forces Ay and MA acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) Determine the bending moment acting at each of the following locations:(a) x = 0+ m (i.e., just to the right of fixed support A)(b) x = 4.0– m (i.e., just to the left of B)(c) x = 4.0+ m (i.e., just to the right of B)(d) x = 6.5 mWhen entering your answers, use the bending moment sign convention.Answers:(a) M = kN-m.(b) M = kN-m.(c) M = kN-m.(d) M = kN-m.
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Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a-9 ft, b-6 ft and w=10.5 kips/ft. Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since A, -0, it has been omitted from the free-body diagram.) Answer: (a) Vi (b) V = i (c) V- a Answers: A, kips, Cy Determine the shear force acting at each of the following locations: (a) x = 0+ ft (i..., just to the right of support A) (b) x-9 ft (c)x=13ft When entering your answers, use the shear force sign convention. kips. kips. kips. b (a) M- (b) M- (c) M-i С Cy The shear-force diagram crosses the V = 0 axis between points A and B. Determine the location x where V = 0 kips. Answer:x-i ft. kip-ft. kip-ft. kip-ft. kips. Determine the maximum bending moment that acts anywhere in the beam. When entering your answer, use the bending moment sign convention.…
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