35. An overflow masonry dam is to be constructed across a stream. The stream is estimated to have a maximum flood discharge of 850m²/s wrhen the elevation of the water sSurface is 345m at the dam site. Six sluice gates each 2.5m high and 2m wide are to be constructed in the dam with their sills at elevation 342m. The main overflow weir for which

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35. An overflow masonry dam is to be constructed across a stream. The
stream is estimated to have a maximum flood discharge of 850m²/s
when the elevation of the water surface is 345m at the dam site. Six
siuice gates each 2.5m high and 2m wide are to be constructed in the
dam with their sills at elevation 342m. The main overflow weir for which
C = 1.45 will be 60m long with a crest elevation at 360m. An auxillary
weir 180m long with a crest elevation at 361m will operate during floods.
For this weir C = 1.88. With all the sluice gates open, what will be the
surface elevation upstream of the dam when the discharge is 850 m³ /s?
c 1.88
w.S.
GIVEN:
c 1.45
h+1
Qr = 850
Q,
Q2
c 0.6
Q,
h, 4 2.5m
42 = 60m
L3 = 180m
C= 1.88
E45
SOLUTION:
3
Q1 = CA/2gh = 0.6(2)(2.5),/19.62(h+ 17.75)(6) = 79.73004453(0.88)ž
%3D
3
3
Q2 = CL2H27 = 1.45(60)(h + 1)7 = 87(h + 1)7
%3D
3
Q3 = CL3H37 = 1.88(180)(h)ĩ = 338.4h.
%3D
%3D
1
3
Qr = Q1 + Q2 + Q3 = 850 = 79.73(h + 17.75)z + 87(h + 1)ž + 338.4h7
%3D
Let h = 0.89
3
3
850= 79.73(0.89 + 17.75)ē + 87(0.89 + 1)ž + 338.4(0.89)7
850< 854.4097694
361 m.
360m.
Transcribed Image Text:35. An overflow masonry dam is to be constructed across a stream. The stream is estimated to have a maximum flood discharge of 850m²/s when the elevation of the water surface is 345m at the dam site. Six siuice gates each 2.5m high and 2m wide are to be constructed in the dam with their sills at elevation 342m. The main overflow weir for which C = 1.45 will be 60m long with a crest elevation at 360m. An auxillary weir 180m long with a crest elevation at 361m will operate during floods. For this weir C = 1.88. With all the sluice gates open, what will be the surface elevation upstream of the dam when the discharge is 850 m³ /s? c 1.88 w.S. GIVEN: c 1.45 h+1 Qr = 850 Q, Q2 c 0.6 Q, h, 4 2.5m 42 = 60m L3 = 180m C= 1.88 E45 SOLUTION: 3 Q1 = CA/2gh = 0.6(2)(2.5),/19.62(h+ 17.75)(6) = 79.73004453(0.88)ž %3D 3 3 Q2 = CL2H27 = 1.45(60)(h + 1)7 = 87(h + 1)7 %3D 3 Q3 = CL3H37 = 1.88(180)(h)ĩ = 338.4h. %3D %3D 1 3 Qr = Q1 + Q2 + Q3 = 850 = 79.73(h + 17.75)z + 87(h + 1)ž + 338.4h7 %3D Let h = 0.89 3 3 850= 79.73(0.89 + 17.75)ē + 87(0.89 + 1)ž + 338.4(0.89)7 850< 854.4097694 361 m. 360m.
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