3.5-3 TCP sequence numbers and ACKs (1). Consider the TCP Telnet scenario below (from Fig. 3.31 in text). Why is it that the receiver sends and ACK that is one larger than the sequence number in the received datagram? 3.5-3 TCP sequence numbers and ACKS (1). Consider the TCP Telnet scenario below (from Fig. 3.31 in text). Why is it that the receiver sends andACK that is one larger than the sequence number in the received datagram?Host AHost BUser types 'C'Sed-42, ACK=79, data = 'C'host ACKS receiptof 'C', echoes back °c'Seq=79, ACKE43, data = 'c'host ACKS receiptof echoed 'C'Seq=43, ACK=80simple telnet scenarioO Because TCP sequence numbers always increase by 1, with every new segment, and the TCP receiver always send the sequence number ofthe next expected segmentBecause the send-to receiver segment carries only one byte of data, and after that segment is received, the next expected byte of data is just thenext byte (i.e., has an index that is one larger) in the data stream.

Here the option # (2) is correct option.

3.5-3 TCP sequence numbers and ACKS (1). Consider the TCP Telnet scenario below (from Fig. 3.31 in text). Why is it that the receiver sends and ACK that is one larger than the sequence number in the received datagram? Host A Host B User types 'c' Sed 42, ACK=79, 4 data = 'c'| host ACKS receipt of 'C', echoes back 'c' Seq=79, ACK 43, data = 'c' host ACKS receipt of echoed 'C' Seq=43, ACK=80 simple telnet scenario Because TCP sequence numbers always increase by 1, with every new segment, and the TCP receiver always send the sequence number of the next expected segment Because the send-to receiver segment carries only one byte of data, and after that segment is received, the next expected byte of data is just the next byte (i.e., has an index that is one larger) in the data stream.

3.5-3 TCP sequence numbers and ACKS (1). Consider the TCP Telnet scenario below (from Fig. 3.31 in text). Why is it that the receiver sends and ACK that is one larger than the sequence number in the received datagram? Host A Host B User types 'c' Sed 42, ACK=79, 4 data = 'c'| host ACKS receipt of 'C', echoes back 'c' Seq=79, ACK 43, data = 'c' host ACKS receipt of echoed 'C' Seq=43, ACK=80 simple telnet scenario Because TCP sequence numbers always increase by 1, with every new segment, and the TCP receiver always send the sequence number of the next expected segment Because the send-to receiver segment carries only one byte of data, and after that segment is received, the next expected byte of data is just the next byte (i.e., has an index that is one larger) in the data stream.

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter9: Computer Networks

Section: Chapter Questions

Problem 10VE

See similar textbooks

Similar questions

SInternet Check sum Consider the figure below (simplex communication scenario). The TCP sender sends an initial window of 4 segments. Suppose the initial value of the sender ན༽)། sequence number, SEQ1, is 100 and the first 4 segments each contain 400 bytes of payload. As you can see ACK 3 is lost. What is the SEQ number (SEQ2, SEQ3, SEQ4, SEQ5) from the Sender and ACK Number (ACK1, ACK2, ACK3, ACK4, ACK5) from the receiver for each segment? Sender Seq1 Seq2 Seq3 Seg4 ACK1 ACK2 ACK3 ACK4 Seq5 ACK5 Receiver
An HTTP client opens a TCP connection using an initial sequence number (ISN) of 14,534 and the ephemeral port number of 59,100. The server opens the connection with an ISN of 21,732. Show the three TCP segments during the connection establishment if the client defines the rwnd of 4000 and the server defines the rwnd of 5000. Ignore the calculation of the checksum field.
Asap
Q1.Suppose a client, say C, has established a TCP connection with a server, say S. After establishing the connection, the sender sends two TCP messages with data back-to-back ( the first TCP message with sequence number 32 and the second TCP message with sequence number 100). a. What is the sequence number chosen by the client? What could be the reason for choosing this value of sequence number?b. What is the data size of first and second TCP data messages?c. Suppose the server receives the first and second TCP messages with data with the difference of 100 milliseconds delay. What could be the ACK number for both the TCP data messages from the server side as per the TCP RFC.
P27. Host A and B are communicating over a TCP connection, and Host B has already received from A all bytes up through byte 126. Suppose Host A then sends two segments to Host B back-to-back. The first and second segments contain 80 and 40 bytes of data, respectively. In the first segment, the sequence number is 127, the source port number is 302, and the destination port number is 80. Host B sends an acknowledgment whenever it receives a segment from Host A. In the second segment sent from Host A to B, what are the sequence number, source port number, and destination port number? If the first segment arrives before the second segment, in the acknowledgment of the first arriving segment, what is the acknowledgment number, the source port number, and the destination port number? If the second segment arrives before the first segment, in the acknowledgment of the first arriving segment, what is the acknowledgment number? Suppose the two segments sent by A arrive in order at B.…
Consider a TCP connection betweek two hosts between A and B. The first data byte sent by A is numbered 1. The LastByteRcvd at B is 500. Then, the range of values SendBase at A may take is from to 500
TCP congestion control example. Consider the figure below, where a TCP sender sends 8 TCP segments at t = 1, 2, 3, 4, 5, 6, 7, 8. Suppose the initial value of the sequence number is 0 and every segment sent to the receiver each contains 100 bytes. The delay between the sender and receiver is 5 time units, and so the first segment arrives at the receiver at t = 6. The ACKs sent by the receiver at t = 6, 7, 8, 10, 11, 12 are shown. The TCP segments (if any) sent by the sender at t = 11, 13, 15, 16, 17, 18 are not shown. The segment sent at t=4 is lost, as is the ACK segment sent at t=7. TCP sender t=1 T t=2 t=3 t=4+ t=5- t=6+ t=11 t=12 t=13 t=14 t=15 t=16 t=17 t=18 I data segment data segment data segment data segment data segment data segment data segment data segment ACK ACK ACK ACK ACK ACK Ty A A V V htt TCP receiver t=6 t=7 t=8 t=9 t=10 t=11 t=12 t=13 What does the sender do at t=17? You can assume for this question that no timeouts have occurred.
TCP congestion control example. Consider the figure below, where a TCP sender sends 8 TCP segments at t = 1, 2, 3, 4, 5, 6, 7, 8. Suppose the initial value of the sequence number is 0 and every segment sent to the receiver each contains 100 bytes. The delay between the sender and receiver is 5 time units, and so the first segment arrives at the receiver at t = 6. The ACKS sent by the receiver at t = 6, 7, 8, 10, 11, 12 are shown. The TCP segments (if any) sent by the sender att = 11, 13, 15, 16, 17, 18 are not shown. The segment sent at t=4 is lost, as is the ACK segment sent at t=7. t=1 T data segment t=2+ data segment data segment-- t=3 TCP sender TCP receiver t=4+ t=5+ data segment - data segment t=6+ t36 data segment t=7 data segment t=8 data segment t=9 ACK + t=10 k -- ACK t=11 t=11 t=12 t=12 t=13 t=13 t=14 ACK -ACK ACK t=15 t=16 t=17 ACK t=18 What does the sender do at t=17? You can assume for this question that no timeouts have occurred.
For NAT Network Address Translation Scenario: Jenny Bello is a small business owner selling and making customized computer peripherals. She has been finding it difficult to track her sales and inventories, however recently after an expert's advice, she adopted a Point of Sale (PoS) server. So, she can now track her sales and inventories at the store. However, she ran into another issue, the server can only be accessed within the store, because it has been assigned a private IPv4 address, it is not publicly accessible via the Internet. a) Why is not having the PoS server accessible over the Internet a problem for the business? b) What caused this problem? c) Propose a solution for the problem and explain how the solution works.
Please solve it correctly and please provide explanation of your answers. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. (d) What will be the window size of PC A after receiving only the first segment from webserver? (e)…
In a TCP data packet, if the sequence number has the value 001111, ACK number has the value 010110 and the urgent pointer has the value 001100 assuming that URG flag is set. What is the last urgent byte in the data section of the packet? All numbers are in binary.
Please solve it correctly and please provide explanation of your answers. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. (a) What will be the sequence number of the third TCP handshake signal send from PC to webserver?…